若x^2+4x+y^2-6Y+13=0,则(x+2y)(x-2y)的值
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若x^2+4x+y^2-6Y+13=0,则(x+2y)(x-2y)的值若x^2+4x+y^2-6Y+13=0,则(x+2y)(x-2y)的值若x^2+4x+y^2-6Y+13=0,则(x+2y)(x-
若x^2+4x+y^2-6Y+13=0,则(x+2y)(x-2y)的值
若x^2+4x+y^2-6Y+13=0,则(x+2y)(x-2y)的值
若x^2+4x+y^2-6Y+13=0,则(x+2y)(x-2y)的值
x^2+4x+y^2-6Y+13=0
(x+2)^2+(y-6)^2=0
x=-2 y=6
(x+2y)(x-2y)
=x^2-4y^2
=4-144
=-140
对,就是配方,把多加的减去,一楼做的是正确的,要想等式等于零成立,则只能是0的平方+0的平方。
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