如何用mathematica求这个积分?Integrate[1/2*Pi*a1^(-1/2)*(1 + 1/a1 ((x - a2)^2 + c))^(-3/2),{x,-Infinity,+Infinity}]

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如何用mathematica求这个积分?Integrate[1/2*Pi*a1^(-1/2)*(1+1/a1((x-a2)^2+c))^(-3/2),{x,-Infinity,+Infinity}]如

如何用mathematica求这个积分?Integrate[1/2*Pi*a1^(-1/2)*(1 + 1/a1 ((x - a2)^2 + c))^(-3/2),{x,-Infinity,+Infinity}]
如何用mathematica求这个积分?
Integrate[1/2*Pi*a1^(-1/2)*(1 + 1/a1 ((x - a2)^2 + c))^(-3/2),{x,-Infinity,+Infinity}]

如何用mathematica求这个积分?Integrate[1/2*Pi*a1^(-1/2)*(1 + 1/a1 ((x - a2)^2 + c))^(-3/2),{x,-Infinity,+Infinity}]
Integrate[
1/2*Pi*a1^(-1/2)*(1 + 1/a1 ((x - a2)^2 + c))^(-3/
2),{x,-Infinity,+Infinity},
Assumptions -> {a1 > 0,a2 > 0,c > 0}]
得到:
(a1*Pi)/(a1 + c)