√2(cos^2a-sin^2a)/(sina-cosa)=-2√2/2,则cosa+sina=?
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/22 12:38:00
√2(cos^2a-sin^2a)/(sina-cosa)=-2√2/2,则cosa+sina=?√2(cos^2a-sin^2a)/(sina-cosa)=-2√2/2,则cosa+sina=?√2
√2(cos^2a-sin^2a)/(sina-cosa)=-2√2/2,则cosa+sina=?
√2(cos^2a-sin^2a)/(sina-cosa)=-2√2/2,则cosa+sina=?
√2(cos^2a-sin^2a)/(sina-cosa)=-2√2/2,则cosa+sina=?
√2(cos^2a-sin^2a)/(sina-cosa)=-2√2/2
=√2(cosa-sina)(cosa+sina)/(sina-cosa)=-√2*(cosa+sina)
故sa+sina=-2√2/2/(-√2)=1
√2(cos^2a-sin^2a)/(sina-cosa)=-2√2/2,则cosa+sina=?√2(cos^2a-sin^2a)/(sina-cosa)=-2√2/2,则cosa+sina=?
sin/cos^2a+cos/sin^2a最小值
求证1+sin a+cos a+2sin acos a/1+sin a+cos a=sin a+cos a
化简 (1+sin a+ cos a)(sin a/2 - cos a/2) / √(2+2cos a)(180°
化简(sin a^2/cos a +cos a)*cot a
求证:sin 2a/1+sin a+cos a=sin a+cos a-1急
sin^4+sin^2cos^2+cos^2a=
求证1/sin^2a+3/cos^2a>=4+2根号下31/sin²a +3/cos²a=(sin²a+cos²a)/sin²a +3(sin²a+cos²a)/cos²a=1+cos²a/sin²a+3+3sin²a/cos²a=4+cos²a/sin²a+3sin²a/cos²a≥4+2√[(cos
一个简单的三角函数题(sin a + cos a)/(sin a - cos a) 则 sin a *cos a=(sin a + cos a)/(sin a - cos a) = 2 则 sin a *cos a=
sin^2(a+pai)-cos(pai+a)*cos(-a)+1
证明Cos^A-Sin^A=1-2Sin^A=2Cos^A-1=cos^a-sin^a
化简:sin(-a)cos(2π+a)sin(-a-π)
化简Sin A + Sin 2A / 1+cos A +
化简sin^2a-cos^2a
cos^2a+sin^2a=?
sin^2A/cos^2A=?
化简sin(a/2)cos(a/2)
求证 1+sin a+cos a+2sin a*cos a/1 +sin a +cos a = sin a+ cos a 有什么思路!
tan a=2,(3sin a-cos a)/(2sin a+cos a)=