x+3y+2z=2,3x+2y-4z=3,2x-y=7的解
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x+3y+2z=2,3x+2y-4z=3,2x-y=7的解x+3y+2z=2,3x+2y-4z=3,2x-y=7的解x+3y+2z=2,3x+2y-4z=3,2x-y=7的解让前两个式子结合消去Z,再
x+3y+2z=2,3x+2y-4z=3,2x-y=7的解
x+3y+2z=2,3x+2y-4z=3,2x-y=7的解
x+3y+2z=2,3x+2y-4z=3,2x-y=7的解
让前两个式子结合消去Z,再和第三个方程结合.
x+3y+2z=2(1),3x+2y-4z=3(2),2x-y=7(3)
(1)X2+(2)得,5x+8y=7 (4)
(3)X8+(4)得,21x=63,所以,x=3,
把x=3代入(3),解得y=-1,
把x=3,y=-1代入(1),解得z=1
所以x=3,y=-1,z=1
x=3,y=-1,z=1
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