｛x=y+1,① 10x+y=10y+x+9,② 请问一下这个方程组怎么解,要有详细过程,谢谢了.

(x+y)/6+(x-y)/10=1,(x+y)/6-(x-y)/10=5 {6/x+y+10/x-y=30 6/x+y-10/x-y=-1 解方程组x+y/6+x-y/10=3,x+y/6+y-x/10=-1x+y/6+x-y/10=3 ①x+y/6+y-x/10=-1 ② x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 y-x=1 10x+y> 10x+y30 10x+y 已知y/x=9/10则(1-y/x)[x/(y-x)]? x+y=20,x-y=10,y= y+10x=x+y+9 10y+x=y+10x+27 y+y+x=10,x+y+x=8,y=?,x=? 已知|x|+x+y=10 |y|+x-y=12 求 x+y=? 已知|x|+x+y=10,|y|+x-y=12,求x+y的值 已知|x|+x+y=10,x+|y|-y=12,求x、y的值 已知/x/+x+y=10,/y/+x-y=12.求x+y的值 (x+y)(x+y-10)+25=0,且x-y=3,求x,y (x+y)(x+y-10)+25=0,且x-y=3,求x,y X+Y-8X+10Y+41=O,求X/Y-Y/X的值 x,y 满足x(x-2)-y(y-6)=-10,求x,y的值 化简 x / y(x+y) - y / x(x+y) =