x-2y+z=-1 x+y+z=2 x+2y+3z=-1
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x-2y+z=-1x+y+z=2x+2y+3z=-1x-2y+z=-1x+y+z=2x+2y+3z=-1x-2y+z=-1x+y+z=2x+2y+3z=-1(1)-(2)得:-3y=-3,则:y=1把
x-2y+z=-1 x+y+z=2 x+2y+3z=-1
x-2y+z=-1 x+y+z=2 x+2y+3z=-1
x-2y+z=-1 x+y+z=2 x+2y+3z=-1
(1)-(2)得:-3y=-3,则:y=1
把y=1代入(1)得:x-2+z=-1
得:x=-z+1
把x=-z+1,y=1代入(3)得:
-z+1+2+3z=-1
2z=-4
z=-2
则:x=3
∴方程组的解为:x=3,y=1,z=-2
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