求(3x-2)(x-3)-2(x+6)(x-5)+3(x-7x+13)的值
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求(3x-2)(x-3)-2(x+6)(x-5)+3(x-7x+13)的值求(3x-2)(x-3)-2(x+6)(x-5)+3(x-7x+13)的值求(3x-2)(x-3)-2(x+6)(x-5)+3
求(3x-2)(x-3)-2(x+6)(x-5)+3(x-7x+13)的值
求(3x-2)(x-3)-2(x+6)(x-5)+3(x-7x+13)的值
求(3x-2)(x-3)-2(x+6)(x-5)+3(x-7x+13)的值
漏了x²把
原式=(3x²-11x+6)-2(x²+x-30)+3x²-21x+39
=3x²-11x+6-2x²-2x+60+3x²-21x+39
=4x²-34x+105
求一个数独答案X X X 9 X X X 8 2 X 6 3 X X 1 4 X 99 X 8 X X X X X XX X X 6 7 X 3 X XX 4 6 X 5 X 2 9 XX X 7 X 2 3 X X XX X X X X X 7 X 17 X 4 3 X X 6 2 X6 3 X X X 7 X X X
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