(2x^2-4x-10xy)÷(?)=(1/2)x-1-(5/2)y

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(2x^2-4x-10xy)÷(?)=(1/2)x-1-(5/2)y(2x^2-4x-10xy)÷(?)=(1/2)x-1-(5/2)y(2x^2-4x-10xy)÷(?)=(1/2)x-1-(5/2

(2x^2-4x-10xy)÷(?)=(1/2)x-1-(5/2)y
(2x^2-4x-10xy)÷(?)=(1/2)x-1-(5/2)y

(2x^2-4x-10xy)÷(?)=(1/2)x-1-(5/2)y
4X
2x*2=1/2
4x=1
10xy=5y/2
由以上可求