Xֲ̬N(122)ȡΪ25ֵС12.5ĸ

0.25n^2+n+11-10x+25x^2-2x^2n-4x^n0.25n^2+n+11-10x+25x^2-2x^2n-4x^n0.25n^2+n+11-10x+25x^2-2x^2n-4x^n您

因式分解15x^(2n+3)-25x^(n+1)+5x^(n-1)因式分解15x^(2n+3)-25x^(n+1)+5x^(n-1)因式分解15x^(2n+3)-25x^(n+1)+5x^(n-1)1

15x^2n+3-25x^n+1+5x^n-1分解因式15x^2n+3-25x^n+1+5x^n-1分解因式15x^2n+3-25x^n+1+5x^n-1分解因式15x^(2n+3)-25x^(n+1

分解因式15x^2n+3-25x^n+1+5x^n-1分解因式15x^2n+3-25x^n+1+5x^n-1分解因式15x^2n+3-25x^n+1+5x^n-1原式=5x^(n-1)*[3x^(2n

15X^N+1-25X^N+5X^N-1分解因式15X^N+1-25X^N+5X^N-1分解因式15X^N+1-25X^N+5X^N-1分解因式15X^N+1-25X^N+5X^N-1=5x^(N-1

15x^2n+3-25x^n+1+5x^n-115x^2n+3-25x^n+1+5x^n-115x^2n+3-25x^n+1+5x^n-115x^(2n+3)-25x^(n+1)+5x^(n-1)=5

15x^2n+3-25x^n+1+5x^n-1分解因式15x^2n+3-25x^n+1+5x^n-1分解因式15x^2n+3-25x^n+1+5x^n-1分解因式15x^(2n+3)-25x^(n+1

计算：(x^n)^n*36x^n计算：(x^n)^n*36x^n计算：(x^n)^n*36x^n我来回答.(x^n)^n=x^2n然后x^2n*x^n=x^3n所以(x^n)^n*36x^n=36x^

计算：(x^n)^n*36x^n计算：(x^n)^n*36x^n计算：(x^n)^n*36x^n(x^n)^n*36x^n=x^n²*36x^n=36x^（n²+n）

X²-25n²-20n-4X²-25n²-20n-4X²-25n²-20n-4X²-25n²-20n-4=x²

因式分解；a^4x^n+2-4x^n（n为正整数）=多少因式分解；25a^n+2-10a^n+1+a^n=多少?因式分解；a^4x^n+2-4x^n（n为正整数）=多少因式分解；25a^n+2-10a

f(x)=e^x-x求证(1/n)^n+(2/n)^n+...+(n/n)^nf(x)=e^x-x求证(1/n)^n+(2/n)^n+...+(n/n)^nf(x)=e^x-x求证(1/n)^n+(2

因式分解：15x的2n+3次方-25x的n+1次方+5x的n-1次方因式分解：15x的2n+3次方-25x的n+1次方+5x的n-1次方因式分解：15x的2n+3次方-25x的n+1次方+5x的n-1

分解因式:15x的n+1次方-25x的n次方+5x的n-1次方分解因式:15x的n+1次方-25x的n次方+5x的n-1次方分解因式:15x的n+1次方-25x的n次方+5x的n-1次方15x^(n＋

x^(n)*x^(n+1)+x^(2n)*xx^(n)*x^(n+1)+x^(2n)*xx^(n)*x^(n+1)+x^(2n)*x解析=x^(n+n+1)+x^(2n+1)=2x^(2n+1)希望对

e^x=1+x+x^2/2!+x^3/3!+...+x^n/n!x=9求和的vb答案是多少n=25e^x=1+x+x^2/2!+x^3/3!+...+x^n/n!x=9求和的vb答案是多少n=25e^

若(x^2+1/x)^n(n∈N+,n若(x^2+1/x)^n(n∈N+,n若(x^2+1/x)^n(n∈N+,n展开式第k项：C(n,k)(x²)^k(1/x)^(n-k)=C(n,k)x

求幂级数(x-3)^n/n^25^n的收敛半径,收敛域求幂级数(x-3)^n/n^25^n的收敛半径,收敛域求幂级数(x-3)^n/n^25^n的收敛半径,收敛域

(x^n+y^n)(x^n-y^n)-(x^n+y^n)²计算.(x^n+y^n)(x^n-y^n)-(x^n+y^n)²计算.(x^n+y^n)(x^n-y^n)-(x^n+y^

因式分解：(x^n+1)+(2x^n)+(x^n-1)因式分解：(x^n+1)+(2x^n)+(x^n-1)因式分解：(x^n+1)+(2x^n)+(x^n-1)X^(n+1)-2X^n+X^(n-1