设f(x)在[0,1]上连续，f(0)两个零点

设f(x)在[0,1]上具有二阶连续导数,且|f''''(x)|设f(x)在[0,1]上具有二阶连续导数,且|f''''(x)|设f(x)在[0,1]上具有二阶连续导数,且|f''''(x)|f(0)=f(x)+

设f(x)在[0,1]上连续,且f(x)设f(x)在[0,1]上连续,且f(x)设f(x)在[1,4]上可导,且1/2∫（2~4）f(x)/xdx=f(1).证明：在（1,4）内至少存在一点t,使f''

高等数学问题：设f(x)在[0,1]上连续,且f(x)高等数学问题：设f(x)在[0,1]上连续,且f(x)高等数学问题：设f(x)在[0,1]上连续,且f(x)设F(x)=2x-∫(x,0)f(t)

设f(x)在[0,1]上有连续导数,f(0)=0,0设f(x)在[0,1]上有连续导数,f(0)=0,0设f(x)在[0,1]上有连续导数,f(0)=0,0令F(x)=(积分(从0到x)f(t)dt)

设f(x)在[0,1]上有连续导数,f(0)=0,0设f(x)在[0,1]上有连续导数,f(0)=0,0设f(x)在[0,1]上有连续导数,f(0)=0,0证：在[0,x]上,根据拉格朗日中值定理f(

设f(x)在[0,1]上连续,试证∫(0,π/2)f(|cosx|)设f(x)在[0,1]上连续,试证∫(0,π/2)f(|cosx|)设f(x)在[0,1]上连续,试证∫(0,π/2)f(|cosx

设f(x)在区间[0,1]上连续,且f0)f(1)设f(x)在区间[0,1]上连续,且f0)f(1)设f(x)在区间[0,1]上连续,且f0)f(1)f(0)f(1)

设f(x)在[0,1]上连续,且f(t)设f(x)在[0,1]上连续,且f(t)设f(x)在[0,1]上连续,且f(t)f(0)=-1f(1)=2-1-∫（0→1）f(t)dt>0又f(x)连续所以在

设f(x)在[0,1]上有连续导数,且f(x)=f(0)=0.证明设f(x)在[0,1]上有连续导数,且f(x)=f(0)=0.证明设f(x)在[0,1]上有连续导数,且f(x)=f(0)=0.证明∵

设f(x)在[0,2]上连续,在(0,2)上可微,且f(0)*f(2)>0,f(0)*f(1)设f(x)在[0,2]上连续,在(0,2)上可微,且f(0)*f(2)>0,f(0)*f(1)设f(x)在

设f(x)在[0,1]上有连续一阶导数,在（0,1）内二阶可导.设f(x)在[0,1]上有连续一阶导数,在（0,1）内二阶可导.设f(x)在[0,1]上有连续一阶导数,在（0,1）内二阶可导.证：因为

设f(x)在[0,1]内连续递减0设f(x)在[0,1]内连续递减0设f(x)在[0,1]内连续递减0因为f(x)递减所以[a,1]内f(x)的积分/1-a

设函数f(x)在[0,无穷)上连续可导,且f(0)=1,|f''(x)|0时,f(x)设函数f(x)在[0,无穷)上连续可导,且f(0)=1,|f''(x)|0时,f(x)设函数f(x)在[0,无穷)上连

设f(x)在区间【0,1】上有连续导数,证明x∈【0,1】,有|f(x)|≤∫(|f(t)|+|f′(t)|)dt设f(x)在区间【0,1】上有连续导数,证明x∈【0,1】,有|f(x)|≤∫(|f(

设f(x)在区间【0,1】上有连续导数,证明x∈【0,1】,有|f(x)|≤∫(|f(t)|+|f′(t)|)dt设f(x)在区间【0,1】上有连续导数,证明x∈【0,1】,有|f(x)|≤∫(|f(

一道高数题,设函数f(x)在[0,+∞)上连续,且f(x)=x(e^-x)+(e^x)∫(0,1)f(x)dx,则f(x)=?设函数f(x)在[0,+∞)上连续,且f(x)=x(e^-x)+(e^x)

求设f''(x)在[0,a]上连续.f(0)=0,证明|定积分f(x)d(x)求设f''(x)在[0,a]上连续.f(0)=0,证明|定积分f(x)d(x)其中M=max|f''(x)|(0求设f''(x)在

设f(x)z[0,1]连续,f(x)设f(x)z[0,1]连续,f(x)设f(x)z[0,1]连续,f(x)设g(x)=2x-∫^(x,0)f(t)dt-1,0F(x)=2x-∫^(x,0)f(t)d

设函数f(x)在闭区间[0,1]上连续,且0设函数f(x)在闭区间[0,1]上连续,且0设函数f(x)在闭区间[0,1]上连续,且0设g(x)=f(x)-x因为0所以g(0)>0,g(1)即在区间上定

设函数f(x)在区间[0,1]上连续,切0设函数f(x)在区间[0,1]上连续,切0设函数f(x)在区间[0,1]上连续,切0令g(x)=2x-∫（0,x）f(t)dt-1则g''(x)=2-f(x)>