an-1=3an-1

已知数列{an}满足a1=1an+1=an/(3an+1)则球an已知数列{an}满足a1=1an+1=an/(3an+1)则球an已知数列{an}满足a1=1an+1=an/(3an+1)则球an求

数列an中,a1=3,an+1=an/2an+1,则an=?数列an中,a1=3,an+1=an/2an+1,则an=?数列an中,a1=3,an+1=an/2an+1,则an=?a(n+1)=an/

已知等差数列{an}中,a1=2.an+1=an+3分之an求an已知等差数列{an}中,a1=2.an+1=an+3分之an求an已知等差数列{an}中,a1=2.an+1=an+3分之an求ana

已知数列{an}a1=3an+1=(3an+2)/(an+2)bn=(an-2)/(an+1)求证bn是等比数列已知数列{an}a1=3an+1=(3an+2)/(an+2)bn=(an-2)/(an

数列｛an｝中,a1=1/23an*an-1+an-an-1=0,通项公式an数列｛an｝中,a1=1/23an*an-1+an-an-1=0,通项公式an数列｛an｝中,a1=1/23an*an-1

A1=1,An+1=3An/(3An+6)证(1/An)+1等比A1=1,An+1=3An/(3An+6)证(1/An)+1等比A1=1,An+1=3An/(3An+6)证(1/An)+1等比a(n+

已知｛an｝,a1=1,an+1=2/3an+1,求an已知｛an｝,a1=1,an+1=2/3an+1,求an已知｛an｝,a1=1,an+1=2/3an+1,求anA(n+1)+x=2/3An+1

an+1,n+1是下表,an+1=an^3a1=2,求anan+1,n+1是下表,an+1=an^3a1=2,求anan+1,n+1是下表,an+1=an^3a1=2,求anan=2^3*（n-1）（

已知数列{an}中a1=1,an+1=3an/an+3,求通项公式已知数列{an}中a1=1,an+1=3an/an+3,求通项公式已知数列{an}中a1=1,an+1=3an/an+3,求通项公式a

在数列an中,a1=1,an=3an-1+2则an=在数列an中,a1=1,an=3an-1+2则an=在数列an中,a1=1,an=3an-1+2则an=an=3an-2+2=>an+1=3(an-

数学已知数列｛an｝,3an+1=an且a2=1,则an=数学已知数列｛an｝,3an+1=an且a2=1,则an=数学已知数列｛an｝,3an+1=an且a2=1,则an=3a(n+1)=ana(n

a1=1,an+1=an/(3+an),求an=?（n为下标）a1=1,an+1=an/(3+an),求an=?（n为下标）a1=1,an+1=an/(3+an),求an=?（n为下标）an+1=an

已知数列{an}中,a1=1/2,an+1+3an=0,an=()已知数列{an}中,a1=1/2,an+1+3an=0,an=()已知数列{an}中,a1=1/2,an+1+3an=0,an=()a

数列an中,a1=3,an+1=3an,则an=,sn=数列an中,a1=3,an+1=3an,则an=,sn=数列an中,a1=3,an+1=3an,则an=,sn=a(n+1)=3ana(n+1)

数列｛an},a1=1,an+1=2an-n^2+3n,求｛an｝.数列｛an},a1=1,an+1=2an-n^2+3n,求｛an｝.数列｛an},a1=1,an+1=2an-n^2+3n,求｛an

数列｛an｝满足a1=1,且an=an-1+3n-2,求an数列｛an｝满足a1=1,且an=an-1+3n-2,求an数列｛an｝满足a1=1,且an=an-1+3n-2,求ana1=1an=an-

a1=1an+1=an/2an+3,用两种方法求an加急加急!a1=1an+1=an/2an+3,用两种方法求an加急加急!a1=1an+1=an/2an+3,用两种方法求an加急加急!方法1：an+

已知{an}中a1=1且an+1=3an+4求an已知{an}中a1=1且an+1=3an+4求an已知{an}中a1=1且an+1=3an+4求ana(n+1)=3an+4.1a(n+2)=3a(n

a1=3,an=2an-1+3证{an+3}等比,并求ana1=3,an=2an-1+3证{an+3}等比,并求ana1=3,an=2an-1+3证{an+3}等比,并求an(1)an=2a+3,∴a

a1=3,an+1=3an/an+2,求ana1=3,an+1=3an/an+2,求ana1=3,an+1=3an/an+2,求an你这题若是a(n+1)=3a(n)/a(n+2),则没法求解若是a(