sinθ·cosθ=1/8;且π/4<θ<π/2求sinθ-cosθ

若sinθ·cosθ=1/8,求sinθ+cosθ?怎样用单位圆确定sinθ和cosθ大若sinθ·cosθ=1/8,求sinθ+cosθ?怎样用单位圆确定sinθ和cosθ谁大谁小?θ属于（π/4，

sinθcosθ=1/8,θ∈(π/4,π/2),求cosθ-sinθ的值sinθcosθ=1/8,θ∈(π/4,π/2),求cosθ-sinθ的值sinθcosθ=1/8,θ∈(π/4,π/2),求

已知向量m=(Cosθ,Sinθ)和n(根号2-Sinθ,Cosθ),且Im+nl=求Cos(θ/2+π/8)已知向量m=(Cosθ,Sinθ)和n(根号2-Sinθ,Cosθ),且Im+nl=求Co

已知tan(θ+π/4)=-2,求cosθ平方+sinθcosθ-1已知tan(θ+π/4)=-2,求cosθ平方+sinθcosθ-1已知tan(θ+π/4)=-2,求cosθ平方+sinθcosθ

已知sin(θ+kπ)=-2cos(θ+kπ)求⑴4sinθ-2cosθ/5cosθ+3sinθ;⑵(1/4)sin平方θ+(2/5)cos平方θ已知sin(θ+kπ)=-2cos(θ+kπ)求⑴4s

2sinθ=cosθ+1,怎么求sin2sinθ=cosθ+1,怎么求sin2sinθ=cosθ+1,怎么求sin用同角三角函数关系式全部展开收起

2sinθ-cosθ=1(sinθ+cosθ+1)/(sinθ-cosθ+1)如题已知2sinθ-cosθ=1求(sinθ+cosθ+1)/(sinθ-cosθ+1)2sinθ-cosθ=1(sinθ

求值:已知sinθ+cosθ=1/5,已知θ∈(0,π).求(1)sinθ*cosθ(2)sinθ-cosθ(3)tanθ求值:已知sinθ+cosθ=1/5,已知θ∈(0,π).求(1)sinθ*c

若2sinθ=cosθ,且θ属于(0,π/2)1.求sinθ-cosθ2.若sin(θ-ψ)=-√10/10若2sinθ=cosθ,且θ属于(0,π/2)1.求sinθ-cosθ2.若sin(θ-ψ)

已知θ∈（π/4,π/2）,且sinθ×cosθ=1/8,则cos²θ×cos²θ－sin²θ×sin²θ=（）已知θ∈（π/4,π/2）,且sinθ×cosθ

sinθcosθ=1/8;且派/4sinθcosθ=1/8;且派/4sinθcosθ=1/8;且派/4先计算cosθ-sinθ的平方,再开方即可,（cosθ-sinθ）^2=cos^2+sin^2+2

2sin(π/4+a)=sinθ+cosθ,且2sin^2b=sin2θ,求sin2a+1/2cos2b2sin(π/4+a)=sinθ+cosθ,且2sin^2b=sin2θ,求sin2a+1/2c

已知sinθ+sin^2θ=1,求3cos^2θ+cos^4θ-2sinθ+1已知sinθ+sin^2θ=1,求3cos^2θ+cos^4θ-2sinθ+1已知sinθ+sin^2θ=1,求3cos^

已知sinθ-cosθ=1/5,且θ∈（0,π）（1）求sinθ+cosθ;（2）求tanθ已知sinθ-cosθ=1/5,且θ∈（0,π）（1）求sinθ+cosθ;（2）求tanθ已知sinθ-c

sinθ·cosθ=1/8;且π/4sinθ·cosθ=1/8;且π/4sinθ·cosθ=1/8;且π/4先计算cosθ-sinθ的平方,再开方即可,（cosθ-sinθ）^2=cos^2+sin^

若sin（θ-π）=2cos（2π-θ）求（1）sinθ+5cosθ/sinθ-3cosθ(2)sinθcosθ的值若sin（θ-π）=2cos（2π-θ）求（1）sinθ+5cosθ/sinθ-3c

已知sin^4θ+cos^4θ=1,求sinθ+cosθ的值已知sin^4θ+cos^4θ=1,求sinθ+cosθ的值已知sin^4θ+cos^4θ=1,求sinθ+cosθ的值sin⁴

已知sinθ-cosθ=1/2,求sin^3θ-cos^3θ已知sinθ-cosθ=1/2,求sin^3θ-cos^3θ已知sinθ-cosθ=1/2,求sin^3θ-cos^3θ根据sinx平方加上

已知向量m=(cosθ,-sinθ),n=(根号2+sinθ,cosθ),θ∈(π,3π/2),且cos(θ/2+π/8)=-4/5,求|m+n|的值谢谢已知向量m=(cosθ,-sinθ),n=(根

请会的大哥大姐多多指教.已知sinθ=(√5-1)/4(1)求(sinθ-cosθ)/(sinθ+cosθ)+(sinθ+cosθ)/(sinθ-cosθ)的值.(2)已知5sinθ+12cosθ=0