4、已知两正弦电流i1=220sin314tA,i2=220sin(314t—120°)A,试写出其

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/22 02:07:13
已知正弦电流i1=70.7sin(347t-30°)A,i2=60sin(314t+60°)A.求正弦电流i1,i2的和已知正弦电流i1=70.7sin(314t-30°)A,i2=60sin(314t+60°)A.求正弦电流i1,i2的和

已知正弦电流i1=70.7sin(347t-30°)A,i2=60sin(314t+60°)A.求正弦电流i1,i2的和已知正弦电流i1=70.7sin(314t-30°)A,i2=60sin(314

已知正弦电流i1=70.7sin(314t-30°)A,i2=60sin(314t+60°)A.求正弦电流i1,i2的和

已知正弦电流i1=70.7sin(314t-30°)A,i2=60sin(314t+60°)A.求正弦电流i1,i2的和已知正弦电流i1=70.7sin(314t-30°)A,i2=60sin(314

正弦电流i1=8 sin( ωt+90°),i2=6 sinωt,i=i1+i2,则i的有效值为正弦电流i1=8sin( ωt+90°),i2=6sinωt,i=i1+i2,则i的有效值为RL串联正弦电路中,已知功率因数等于0.则R:XL=

正弦电流i1=8sin(ωt+90°),i2=6sinωt,i=i1+i2,则i的有效值为正弦电流i1=8sin(ωt+90°),i2=6sinωt,i=i1+i2,则i的有效值为RL串联正弦电路中,

1、已知两正弦交流电流i1 = 5 sin(314t+60) A,i2 = 10 sin(314t-30) A,则二者的相位关系是?

1、已知两正弦交流电流i1=5sin(314t+60)A,i2=10sin(314t-30)A,则二者的相位关系是?1、已知两正弦交流电流i1=5sin(314t+60)A,i2=10sin(314t

已知两个正弦量分别为i1=-4cos(100t+60°)A,i2=sin(100t+60°)A,则i1的相位相对i2的相位滞后多少度

已知两个正弦量分别为i1=-4cos(100t+60°)A,i2=sin(100t+60°)A,则i1的相位相对i2的相位滞后多少度已知两个正弦量分别为i1=-4cos(100t+60°)A,i2=s

已知正弦交流电流i1=10sin(at+45°)A,i2=10sin(at-45°)A,则i=i1+i2=?A.

已知正弦交流电流i1=10sin(at+45°)A,i2=10sin(at-45°)A,则i=i1+i2=?A.已知正弦交流电流i1=10sin(at+45°)A,i2=10sin(at-45°)A,

正弦稳态电路 若电流i=i1+i2,且i1=10sinωt A,i2=10sinω A,则i的有效值为

正弦稳态电路若电流i=i1+i2,且i1=10sinωtA,i2=10sinωA,则i的有效值为正弦稳态电路若电流i=i1+i2,且i1=10sinωtA,i2=10sinωA,则i的有效值为正弦稳态

已知两个正弦量为i1=10sin(314t-90º)A,i2=10sin(628t-30º)A.正确的是()A i1比i2超前60º B i1比i2滞后60º C i1比i2超前90º D不能判断相差位

已知两个正弦量为i1=10sin(314t-90º)A,i2=10sin(628t-30º)A.正确的是()Ai1比i2超前60ºBi1比i2滞后60ºCi1比

-.正弦交流电路题目u=220根号2sin314t V,i1=22sin(314t-45°)i2=sin(314t+90°)A,求电压表,电流表的读数及电路参数R、u、和C交流电路.一条支路上是电流表A2和电容器C串联(通过的是电流i2),一条支

-.正弦交流电路题目u=220根号2sin314tV,i1=22sin(314t-45°)i2=sin(314t+90°)A,求电压表,电流表的读数及电路参数R、u、和C交流电路.一条支路上是电流表A

已知正弦电流i1=31.1sin(314t+20度)A,i2=10倍根号2sin(314t-70度)A.写出它们的最大值、有效值、角频率、周期、初相位及相位差,并画出波形图.(要整个过程,要详细点)先谢谢了

已知正弦电流i1=31.1sin(314t+20度)A,i2=10倍根号2sin(314t-70度)A.写出它们的最大值、有效值、角频率、周期、初相位及相位差,并画出波形图.(要整个过程,要详细点)先

已知正弦电流i1=20根号2sin(314t+60°)A,i2=30sin(314t-90°)A,用电流表分表测两电流值,读数应该是20a,21.2a,请麻烦写下具体的解答步骤.

已知正弦电流i1=20根号2sin(314t+60°)A,i2=30sin(314t-90°)A,用电流表分表测两电流值,读数应该是20a,21.2a,请麻烦写下具体的解答步骤.已知正弦电流i1=20

两电阻并联,已知R1:R2=3:4,电流I1比I2多6A,求I1和I2

两电阻并联,已知R1:R2=3:4,电流I1比I2多6A,求I1和I2两电阻并联,已知R1:R2=3:4,电流I1比I2多6A,求I1和I2两电阻并联,已知R1:R2=3:4,电流I1比I2多6A,求

已知两个正弦量为I1=10sin(314t+90度)安,I2=10sin(628t+30度)安那么I1超前I2 60度 I1滞后I2 60度 I1超前I2 90度 或不能叛断相位差 以上四个哪 个对已知两个正弦量为I1=10sin(314t+90度)安,I2=10sin(628t+30度)安,

已知两个正弦量为I1=10sin(314t+90度)安,I2=10sin(628t+30度)安那么I1超前I260度I1滞后I260度I1超前I290度或不能叛断相位差以上四个哪个对已知两个正弦量为I

已知正弦电流i=25sin(100t+38')A,试写出其振幅值、角频率和初相.

已知正弦电流i=25sin(100t+38'')A,试写出其振幅值、角频率和初相.已知正弦电流i=25sin(100t+38'')A,试写出其振幅值、角频率和初相.已知正弦电流i=25sin(100t+3

已知i1=14.1sin(628t-50°)A,i2=70.7sin(628t+40°)A,i=i1+i2,求i最大值,有效值,

已知i1=14.1sin(628t-50°)A,i2=70.7sin(628t+40°)A,i=i1+i2,求i最大值,有效值,已知i1=14.1sin(628t-50°)A,i2=70.7sin(6

三个频率均为50Hz的正弦交流电流i1,i2,i3,其振幅值分别为0.05A,0.5A和1A,已知i1超前i2 30度,滞后i3 60度,如果以i3为参考正弦量,试写出i1,i2,i3的瞬时表达式?

三个频率均为50Hz的正弦交流电流i1,i2,i3,其振幅值分别为0.05A,0.5A和1A,已知i1超前i230度,滞后i360度,如果以i3为参考正弦量,试写出i1,i2,i3的瞬时表达式?三个频

已知一正弦电流i=10 sin⁡(314t-π/6)A ,写出其振幅值、角频率、频率、周期及相值.

已知一正弦电流i=10sin⁡(314t-π/6)A,写出其振幅值、角频率、频率、周期及相值.已知一正弦电流i=10sin⁡(314t-π/6)A,写出其振幅值、角频率、频率、

同频率正弦量i1与i2 ,相位关系是反相,若 i1=2 sin(ωt-70)A,则i2 的初相位为 .

同频率正弦量i1与i2,相位关系是反相,若i1=2sin(ωt-70)A,则i2的初相位为.同频率正弦量i1与i2,相位关系是反相,若i1=2sin(ωt-70)A,则

正弦电流i1=100sin(wt+45),i2=60sin(wt-30).i=i1+i2怎样用相量图求解?

正弦电流i1=100sin(wt+45),i2=60sin(wt-30).i=i1+i2怎样用相量图求解?正弦电流i1=100sin(wt+45),i2=60sin(wt-30).i=i1+i2怎样用

已知i2=7sin(wt+30°)A,i2=4sin(wt+150°),i=i1+i2.利用相量法求I速速速、、、

已知i2=7sin(wt+30°)A,i2=4sin(wt+150°),i=i1+i2.利用相量法求I速速速、、、已知i2=7sin(wt+30°)A,i2=4sin(wt+150°),i=i1+i2