代数因式分解 a(x-1)-x+1 4x^5y^3-6x^4y^4+12x^3y^5a(x-1)-x+1 4x^5y^3-6x^4y^4+12x^3y^5

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代数因式分解a(x-1)-x+14x^5y^3-6x^4y^4+12x^3y^5a(x-1)-x+14x^5y^3-6x^4y^4+12x^3y^5代数因式分解a(x-1)-x+14x^5y^3-6x

代数因式分解 a(x-1)-x+1 4x^5y^3-6x^4y^4+12x^3y^5a(x-1)-x+1 4x^5y^3-6x^4y^4+12x^3y^5
代数因式分解 a(x-1)-x+1 4x^5y^3-6x^4y^4+12x^3y^5
a(x-1)-x+1
4x^5y^3-6x^4y^4+12x^3y^5

代数因式分解 a(x-1)-x+1 4x^5y^3-6x^4y^4+12x^3y^5a(x-1)-x+1 4x^5y^3-6x^4y^4+12x^3y^5
a(x-1)-x+1
=a(x-1)-(x-1)
=(x-1)(a-1)
4x^5y^3-6x^4y^4+12x^3y^5
=2x^3y^3(2x^2-3xy+6y^2)

a(x-1)-x+1
= a(x-1)-(x-1 )
=(x-1)(a-1)
4x^5y^3-6x^4y^4+12x^3y^5
=2x³y³(2x²-3xy+6y²)
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a(x-1)-x+1
= a(x-1)-(x-1 )
=(x-1)(a-1)
4x^5y^3-6x^4y^4+12x^3y^5
=2x³y³(2x²-3xy+6y²)
很高兴为您解答,祝你学习进步!【学习宝典】团队为您答题。
有不明白的可以追问!如果您认可我的回答。
请点击下面的【选为满意回答】按钮,谢谢!

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