设数列{an}的前n项和为Sn,且(3-m)Sn+2MAn=m+3(m∈N*),其中m为常数且m≠-3,求证:{an}为等比数列.
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设数列{an}的前n项和为Sn,且(3-m)Sn+2MAn=m+3(m∈N*),其中m为常数且m≠-3,求证:{an}为等比数列.设数列{an}的前n项和为Sn,且(3-m)Sn+2MAn=m+3(m
设数列{an}的前n项和为Sn,且(3-m)Sn+2MAn=m+3(m∈N*),其中m为常数且m≠-3,求证:{an}为等比数列.
设数列{an}的前n项和为Sn,且(3-m)Sn+2MAn=m+3(m∈N*),其中m为常数且m≠-3,求证:{an}为等比数列.
设数列{an}的前n项和为Sn,且(3-m)Sn+2MAn=m+3(m∈N*),其中m为常数且m≠-3,求证:{an}为等比数列.
证:
n=1时,
(3-m)S1+2ma1=(3-m)a1+2ma1=3a1+ma1=m+3
a1(m+3)=m+3
m≠-3,a1=1
n≥2时,
(3-m)Sn+2man=m+3 (1)
(3-m)S(n-1)+2ma(n-1)=m+3 (2)
(1)-(2)
(3-m)an+2man-2ma(n-1)=0
(m+3)an=2ma(n-1)
an/a(n-1)=2m/(m+3),为定值.
数列{an}是以1为首项,2m/(m+3)为公比的等比数列.
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