若角α,β满足-π/2＜α＜β＜π/2,则2α－β的取值范围是

来源：学生作业帮助网编辑：六六作业网时间：2024/11/07 21:47:09

若角α,β满足-π/2＜α＜β＜π/2,则2α－β的取值范围是若角α,β满足-π/2＜α＜β＜π/2,则2α－β的取值范围是若角α,β满足-π/2＜α＜β＜π/2,则2α－β的取值范围是∵-π/2∴-

若角α,β满足-π/2＜α＜β＜π/2,则2α－β的取值范围是
若角α,β满足-π/2＜α＜β＜π/2,则2α－β的取值范围是

若角α,β满足-π/2＜α＜β＜π/2,则2α－β的取值范围是
∵ - π / 2 < a < π / 2
∴ - π < 2 a < π
∵ - π / 2 < b < π / 2
∴ - 3 π / 2 < 2 a - b < π/2
希望你会学的更好.

-π/2＜α＜π/2, 不等式同乘以2，不等号方向不变，所以得到-π＜2α＜π
-π/2＜β＜π/2, 不等式同乘以-1，不等号方向改变，-π/2*(-1)>-β>π/2*(-1),
所以得到-π/2＜-β＜π/2

所以-π＜2α＜π
-π/2＜-β＜π/2

两式相加，得到-π+(-π/2)<2α+(-β)<π+π/2<...

全部展开

收起

∵ - π / 2 < a < π / 2
∴ - π < 2 a < π
∵ - π / 2 < b < π / 2
∴ - 3 π / 2 < 2 a - b < 3 π / 2

若角α,β,满足-π/2 若角α,β满足-π/2 若角α,β满足π/-2 若角α、β满足π/-2 若角α、β满足π/-2 若角α,β满足-π 若α,β 满足-π/2 设α,β满足条件-π/2 设α,β满足条件-π/2 若角a,β 满足 -π/2 若角α,β满足-π/2＜α＜β＜π/2,则2α－β的取值范围是若α,β满足π/2我刚刚发错了。其实是，若α,β满足-π/2 不等式 (24 20:6:15)若角α,β满足-π/2 设角α,β满足-π/2＜α＜β＜π/2,则α-β的取值范围若角α、β满足-90°＜α＜β＜90°,则2α-β的取值范围是_________理由? 若角A,B满足-π/2 若角A、B满足-π/2 若角A、B满足-π/2