若角A,B满足-π/2

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若角A,B满足-π/2若角A,B满足-π/2若角A,B满足-π/2因为-π/2所以-π/2因为-π/2所以-π因为A所以A-B所以-π

若角A,B满足-π/2
若角A,B满足-π/2

若角A,B满足-π/2
因为 -π/2 < B < π/2
所以 -π/2 < -B < π/2
因为 -π/2 < A < π/2
所以 -π< A - B < π
因为 A < B
所以 A - B < 0
所以 -π< A - B < 0

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