若角A.B满足-π/2-π/2-

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若角A.B满足-π/2-π/2-若角A.B满足-π/2-π/2-若角A.B满足-π/2-π/2-∵-π/2-π/2-π-π/2所以-π/2-相加-3π/2所以是(-3π/2,3π/2)

若角A.B满足-π/2-π/2-
若角A.B满足-π/2
-π/2-

若角A.B满足-π/2-π/2-
∵ -π/2

-π/2-π<2A<π
-π/2所以-π/2-相加
-3π/2<2A-B<3π/2
所以是(-3π/2,3π/2)

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