函数y=log(1/3)[sin(π/4-π/3)]的单调递增区间是( ),求详解,

来源:学生作业帮助网 编辑:六六作业网 时间:2024/07/04 06:28:47
函数y=log(1/3)[sin(π/4-π/3)]的单调递增区间是(),求详解,函数y=log(1/3)[sin(π/4-π/3)]的单调递增区间是(),求详解,函数y=log(1/3)[sin(π

函数y=log(1/3)[sin(π/4-π/3)]的单调递增区间是( ),求详解,
函数y=log(1/3)[sin(π/4-π/3)]的单调递增区间是( ),求详解,

函数y=log(1/3)[sin(π/4-π/3)]的单调递增区间是( ),求详解,

题目不全,请核对题目后追问.(缺少自变量x)