log2(x-2)
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log2(x-2)log2(x-2)log2(x-2)log2(x-2)log2(x-2)log2(x-2)得到,x-2>8x>10log2(x-2)x-2>8x>10如果是以2为底,(x-2)x首先
log2(x-2)
log2(x-2)
log2(x-2)
log2(x-2)
log2(x-2)<3等于,
log2(x-2)
x>10
log2(x-2)
x>10
如果是以2为底,(x-2)<2^3=8
x<10
首先x-2.>0得X>2
其次是增函数X-2<8得X<10,所以2
2的三次方
log2(x-3)
x<11
∵x-2>0
∴X>2
∵log2(x-2)为增函数
∴x-2>8
即x>10
|2x-log2^x|
|[log2(x)]^2-3log2(x)+1|
化简:(log2(x/4))*(log2(x/2))
log2(2X-1)
log2(x^2)图像
log2(x-2)
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5)
log2 4+log2 (x+2)怎么算?log2 4+log2 (x+2)=log2 (4x+8)
不等式|2x-log2^x|
log2(2x)*log2(x)=2 x=?
f(x)=log2(x/8)*log2(2/x)
log2(x2-x-2)>log2(2x-2)解不等式
log2 (2^x-1)·log2 [2^(x+1)-2]
log2 (2^x-1)·log2 [2^(x+1)-2]
log2(x-1)>2定义域log2(x-1)>2 定义域
解不等式2log2 (x-4)< log2 (x-2)