(x-6)(y+12)=(x+4)(y-4)=xy 谁来教教我?
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(x-6)(y+12)=(x+4)(y-4)=xy谁来教教我?(x-6)(y+12)=(x+4)(y-4)=xy谁来教教我?(x-6)(y+12)=(x+4)(y-4)=xy谁来教教我?应把原方程拆成
(x-6)(y+12)=(x+4)(y-4)=xy 谁来教教我?
(x-6)(y+12)=(x+4)(y-4)=xy
谁来教教我?
(x-6)(y+12)=(x+4)(y-4)=xy 谁来教教我?
应把原方程拆成两个新方程(x-6)(y+12)xy和(x+4)(y-4)=xy
再分别解这两个方程,会发现xy项消没了,再将化减后的两个方程连立,从而组成一个二元一次方程组,这样你就会做了.Αガ
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