(3xy^2)^3乘[xy(2x-y)-2x(xy-y^2)].其中x=2 y=1/2
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(3xy^2)^3乘[xy(2x-y)-2x(xy-y^2)].其中x=2y=1/2(3xy^2)^3乘[xy(2x-y)-2x(xy-y^2)].其中x=2y=1/2(3xy^2)^3乘[xy(2x
(3xy^2)^3乘[xy(2x-y)-2x(xy-y^2)].其中x=2 y=1/2
(3xy^2)^3乘[xy(2x-y)-2x(xy-y^2)].其中x=2 y=1/2
(3xy^2)^3乘[xy(2x-y)-2x(xy-y^2)].其中x=2 y=1/2
x=2 y=1/2
所以xy=1
所以(3xy²)³*[xy(2x-y)-2x(xy-y²)]
=(3y)³*[(2x-y)-2x(1-y²)]
=27y³*(2x-y-2x+2xy²)
=27y³*(-y+2y)
=27y⁴
=27*(1/2)⁴
=27/16
如果不懂,祝学习愉快!
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