若(x+y)-2xy+2x-8y+17=0,求x的y次方
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若(x+y)-2xy+2x-8y+17=0,求x的y次方若(x+y)-2xy+2x-8y+17=0,求x的y次方若(x+y)-2xy+2x-8y+17=0,求x的y次方应该是(x+y)^2-2xy+2
若(x+y)-2xy+2x-8y+17=0,求x的y次方
若(x+y)-2xy+2x-8y+17=0,求x的y次方
若(x+y)-2xy+2x-8y+17=0,求x的y次方
应该是(x+y)^2-2xy+2x-8y+17=0吧
展开并整理得x^2+2x+1+y^2-8y+16
(x+1)^2+(y-4)^2=0
由题意得
x+1=0 或y-4=0
解得x=-1 y=4
所以x^y=1
题目掉了一个平方
(x+y)2-2xy+2x-8y+17=0
x^2+2xy+y^2-2xy+2x-8y+17=0
x^2+2x+1 + y^2 -8y+16=0
(x+1)^2 + (y+4)^2=0
即 x=-1 y=-4
x^y=(-1)^(-4)=1
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