1/4+1/(4*7)+1/(7*10)+1/(10*13)+...+1/(3n-2)*(3n+1)
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1/4+1/(4*7)+1/(7*10)+1/(10*13)+...+1/(3n-2)*(3n+1)1/4+1/(4*7)+1/(7*10)+1/(10*13)+...+1/(3n-2)*(3n+1)
1/4+1/(4*7)+1/(7*10)+1/(10*13)+...+1/(3n-2)*(3n+1)
1/4+1/(4*7)+1/(7*10)+1/(10*13)+...+1/(3n-2)*(3n+1)
1/4+1/(4*7)+1/(7*10)+1/(10*13)+...+1/(3n-2)*(3n+1)
#include
void main()
{int int xp(int),i,n,sum;
scanf("%d",&n);
sum=int xp(n);
printf("sum=%d",sum);
}
void main(int n)
{double i;
for(i=1;i
1/1*4+1/4*7+1/7*10+1/10*13+~+1/97*100
1/1*4+1/4*7+1/7*10+1/10*13+…+1/298*301
1/4*1+1/4*7+1/7*10+1/10*13+1/13*16=?
1/1*4+1/4*7+1/7*10+1/10*13+1/13*16
7/10*3/7-1/4+7/10简算?
1/4+1/4*1/7+1/7*1/10+...1/25*1/28=?
1/1*4+1/4*7+1/7*10+.+1/2005*2008 1/1*4+1/4*7+1/7*10+.+1/2005*2008
1/4*+1/4*7+1/7*10+1/10*14+.+1/91*94=
1/1*4+1/4*7+1/7*10+.+1/52*55*+1/55*58=?
1/1×4+1/4×7+1/7×10+.+1/52×55+1/55×58
1如何计算1*1/4+4*1/7+7*1/10+...+2002*1/2005
计算1/1*4+1/4*7+1/7*10+...+1/2005*2008+1/2008*2011
1/1×4+1/4×7+1/7×10+...+1/22×25+1/25×28
1/1*4+1/4*7+1/7*10+.1/2002*2005+1/2005*2008
(4/5+1/4)/3/7+7/10简算
4/7+3/10*7/4+1/6简算
1/4+4/7+7/10+.97/100=
（4/5+1/4）÷7/3+7/10