a=log3(10),b=log3(7),则3^a-b=?

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a=log3(10),b=log3(7),则3^a-b=?a=log3(10),b=log3(7),则3^a-b=?a=log3(10),b=log3(7),则3^a-b=?3^(a-b)=3^(lo

a=log3(10),b=log3(7),则3^a-b=?
a=log3(10),b=log3(7),则3^a-b=?

a=log3(10),b=log3(7),则3^a-b=?
3^(a-b)
=3^(log3(10)-log3(7))
=3^[log3(10/7)]
=10/7


3^a-b
=3^a/3^b
=3^log3(10)/3^log3(7)
=10/7

3^(a-b)=(3^a)/(3^b)=10/7