((1-x^2)/(1+x^2))^0.5 再乘以x,求积分,急用

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((1-x^2)/(1+x^2))^0.5再乘以x,求积分,急用((1-x^2)/(1+x^2))^0.5再乘以x,求积分,急用((1-x^2)/(1+x^2))^0.5再乘以x,求积分,急用∫√[(

((1-x^2)/(1+x^2))^0.5 再乘以x,求积分,急用
((1-x^2)/(1+x^2))^0.5 再乘以x,求积分,急用

((1-x^2)/(1+x^2))^0.5 再乘以x,求积分,急用
∫√[(1-x^2)/(1+x^2)]xdx
=(1/2)∫√[(1-x^2)/(1+x^2)dx^2
x^2=cosu
=(1/2)∫√[(1-cosu)/(1+cosu)] dcosu
=(1/2)∫[sin(u/2)/cos(u/2)]*(-sinu)du
=∫(sinu/2)^2du
=(1/2)∫(1-cosu)du
=(1/2)u+(1/2)sinu+C
=(1/2)arccos(x^2)+(1/2)√(1-x^2)+C

=(-1/2)arcsin(x^2)+(1/2)√(1-x^2)+C

一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x 七年级下册政治复习提纲(山东人民出版社)第五单元是 青春的脚步 青春的气息别弄错了啊!格式:X X X X X X X X X 1、X X X X X X X X X X.2、X X X X X X X X X.3、X X X X X X X X X X X. 解九宫格题目(X为未知数)9 X 2 X 7 X 8 X XX X 4 X X 9 X 6 X1 3 X 5 X X X X 24 X X 8 5 X X 1 XX 8 9 4 X 1 6 7 XX 1 X X 3 6 X X 88 X X X X 2 X 3 6X 5 X 6 X X 9 X XX X 7 X 4 X 2 X 1 请问这道题咋做 :(x)X (x+1) X (x+2) X (x+3) =360 分解因式----(X*X-X)(X*X-X-2)+1 35道.符号^代表平方.读起来就是(X的平方).1,x^-x-202,x^-9x+203,x^-9x-204,x^+9x+205,x^-18x+326,x^+14x-317,x^+18x+328,x^+14x-329,x^+19x+4810,x^+47x-4811,x^+13x-4812,x^+2x-4813,x^+26x+4814,x^-22x-4815,x^+17x+7216,x^+21x-10017,x^-x-7218,x 】x(x+1)+x^2(x-1) 1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做 已知1/√(x)+√(x)=√5,求√(x/x2+x+1)+√(x/x2-x+1)的值定义域 x>0,两边平方,x+2+1/x=5,x+1/x=3,x^2-3x+1=0,x^2+x+1-4x=0,x^2+x+1=4x,x^2-x+1-2x=0.x^2-x+1=2x,√[x/(x^2+x+1)]-√[x/(x^2-x+1)]=√[x/(4x)]-√[x/2x]=√(1/4)-√(1/2) (x-1)^3(x+1)(x-2)/(x+4) x(x+1)(x+2)(x+3)+1 (换元法) 因式分解(x+x)-(x+x-1)-2 计算 x(x+3)-(x-1)(x-2) 化简:x(2x+1)-x(x-3) (x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3)(x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3) 先化简,再求值(x²+x+1分之x²-4)÷(x³+x²+x分之x³-2x²)²乘以(x+2)³分之x,其中x²+2x-2=0.