4x+2y+5z=1 x-2y-2z=2 3x+2y-z=5三元一次方程
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/29 05:03:43
4x+2y+5z=1x-2y-2z=23x+2y-z=5三元一次方程4x+2y+5z=1x-2y-2z=23x+2y-z=5三元一次方程4x+2y+5z=1x-2y-2z=23x+2y-z=5三元一次
4x+2y+5z=1 x-2y-2z=2 3x+2y-z=5三元一次方程
4x+2y+5z=1 x-2y-2z=2 3x+2y-z=5
三元一次方程
4x+2y+5z=1 x-2y-2z=2 3x+2y-z=5三元一次方程
4x + 2y + 5z = 1 (1)
x - 2y - 2z = 2 (2)
3x + 2y -z = 5 (3)
(1) + (2)得：5x + 3z = 3 (4)
(2) + (3)得:4x - 3z = 7 (5)
( 4) + (5)得：9x = 10 解得：x = 10/9
将 x = 10/9代入（4）得 3z = 3 - 5x 则z = (3 - 5x)/3 = (3 - 5×10/9)/3 = -23/27
把x = 10/9 z = -23/27代入（1）得：2y = 1 - 4x - 5z
y ＝ （1 －4x - 5z)/2
= (1 - 4× 10/9 - 5×(-23/27) )/2
= 11/27
所以,原方程组的解是 x = 10/9 y = 11/27 z = -23/27
3x-y+2z=-1 4x+y+z=5 x-2y-z=-2
5x+y+z=1 2x-y+2z=1 x+5y-z=4
x-y+z=-1 5x+2y-z=6 4x-3y+2z=-5
x+y+z=-1 4x-2y+3z=5 y-z=8-2x
x+y+z=-5,3x+y+z=1,4x+3y+2z=-2快
x+y+z=1 4x+5y-z=6 x+2y-z=3
{x+y+z=1 {x+3y+7z=2 {x+5y+19z=4
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
1.{x:y:z=3:4:5 2x+3y-5z=-142.{x-y-z=-1 3x+5y+7z=11 4x-y+2z=-13.{x+y=1 x+z=0 2x+y+2z=44.{x-y+z=-3 2x-y-z=-2 -3x+y+z=-15.{x-y+z=-3 3x+y-4z=6 2x+y-z=36.{x-2y+5z=16 2x+y-5z=7 2x-y+z=38
三元一次方程组{5x+y+z=1 2x-y+2z=1 x+5y-z=4 求X Y Z的值
x-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 分别求出x=?y=?z=?
三元一次方程 X-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 X=?Y=?Z=?
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
x/2=y/3=z/5 x+3y-z/x-3y+z
已知x:：y：z=3：4：5,(1)求x+y分之z的值；（2）若x+y+z=6,求x,y,z.
若x,y,z成等差数列,则(z-x)^2-4(x-y)(y-z)=
(x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z