x+6y=-6,x+3z-2y=16,2x+z+y=12.

如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y, x+y+z=6 x+2y+3z=14 y+1=z 1.{x:y:z=3:4:5 2x+3y-5z=-142.{x-y-z=-1 3x+5y+7z=11 4x-y+2z=-13.{x+y=1 x+z=0 2x+y+2z=44.{x-y+z=-3 2x-y-z=-2 -3x+y+z=-15.{x-y+z=-3 3x+y-4z=6 2x+y-z=36.{x-2y+5z=16 2x+y-5z=7 2x-y+z=38 方程组：{x+y-z=6,x+z=16,x-y+2z=17 若X:Y:Z=5:6:7那么(Y-X):(Y+Z)和(X+2Y+3Z):(3X+2Y+Z) 解方程组2x=3y=6z,x+2y+z=16 3x-y+z=4,2z+3y-z=12,x+y+z=6的解 已知x、y、z满足方程组：x+y-z=6；y+z-x=2；z+x-y=0 求x、y、z的值 已知X.Y.Z满足方程组,X+y-Z=6y+z-x=2z+x-y=0求X.Y.Z的值 三元一次方程x+y+z=0 4x+2y+z=3 9x+3y+z=6x+y+z=04x+2y+z=3 9x+3y+z=6 x+6y=-6,x+3z-2y=16,2x+z+y=12. {x-y+z=6,x+3y=-1,y+2z=3 (1)X+Y=15,Y+Z=-6,Z+X=7.(2)X+Y=-14,Y+Z=-7,Z+X=9.(3)X+Y=0,Y+Z=-1,Z+X=-1. x/6=y/4=z/3,则(x+3y)/(3y-2z) 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z 2x-y+2z=6 3x+y-3z=-4 x+y+z=6 2x-3y-z=-6 7x-y+2z=-17 x-y+z=-6