A=1/(2^10 +1) +1/(2^10 +2)+……1/(2^11),则A与1的大小关系是?

【1】a+a=a×a a= [ ]【2】a×a=a÷a a=[ ]【3】a×a=a－a a=[ ] [4]a－a=a＋a a=[ ] a+a+1+a+2+a+3+a+4+a+5+a+6+a+7.+a+2013+a+2014=? [(a/a-2)-(a/a+2)]÷4a/2-a,其中a=-1/2 已知a×a+a-1=0求a*a*a+2a+3 a=-1 求a-2a+3a-4a+5a-6a+...+99a-100a (a 1)(a 2)(a 3)(a (a+2)(a+1)-a(a-3) A^2+(A+1)^2+(A+A^2)^2=? 1a+1a=2a a=? 2a(a-2)-(a+1)(a-3)=? a-1/a=2 若a^2-10a+1=0,求a^2+1/a^2和(a-1/a)^2 {1,a,b/a}={0,a^2,a+b} 先化简,再求值:(a-1/a-a-2/a+1)÷2a^2-a/a^+2a+1,其中a满足a^2-a-1=0 先化简,再求值[(a^3+2a^2+4a)/(a-2)(a^2+2a+4)]-10/(a^2+a-6)除以[1-21/(a^2-4)]*(a+3)/(a-2),其中a=1/2 先化简,再求值[(a^3+2a^2+4a)/(a-2)(a^2+2a+4)]-10/(a^2+a-6)除以[1- 21/(a^2-4)]*(a+3)/(a-2),其中a=1/2 (a+1/a^2-1 +1)×a^2-2a+1/a,其中a=2 (a-2/a^2+2a-a-1/a^2+4a+4)除以a-4/a+2,其中a满足a^2+2a-1=0