log4(1+√5-√3)+log4(1+√5+√3)=?
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log4(1+√5-√3)+log4(1+√5+√3)=?log4(1+√5-√3)+log4(1+√5+√3)=?log4(1+√5-√3)+log4(1+√5+√3)=?log4(1+√5-√3)
log4(1+√5-√3)+log4(1+√5+√3)=?
log4(1+√5-√3)+log4(1+√5+√3)=?
log4(1+√5-√3)+log4(1+√5+√3)=?
log4(1+√5-√3)+log4(1+√5+√3)
=log4[(1+√5-√3)(1+√5+√3)]
=log4[(1+√5)²-3)]
=log4(1+2√5+5-3)
=log4(2√5+3)
若√5是√2
log4(1+√2+√3)+log4(1+√2-√3)
=log4[(1+√2+√3)(1+√2-√3)]
=log4[(1+√2)²-3]
=log4[1+2√2+2-3]
=log4(2√2)
=log4[2^(3/2)]
=log4[4(3/4)]
=(3/4)log4(4)
=3/4
log4(1+√5-√3)+log4(1+√5+√3)=?
(1/4)^log4(3)
log4(1+√2+√3)+log4(1+√2-√3)的值等于
求证:log4 3*log4 5
解方程log4 x+1/log4 x=10/3
解方程 log4 (3x-1)=log4 (x-1)+log4 (3+x)
log4(3x-1)-log4(3+x)=log4(x-1)
log4(√5-√3)+log4(√5+√3)=?
log4^(-1)等于几
log4^(-1)等于几
log4 1/8
log4
解方程:log2(3-x) - log4(x+5) =1
求证log3(4)=1/log4(3)
比较log3 4与log5 6 大小还有log3 4与log4 5 的大小 看我做的 我用作商法 log4 5 ÷log3 4 =log4 5×log4 3 =log4 8=3÷2>1 ∴log4 5大于log3 4 帮忙看看错在哪里
log4(3x+1)+log4(x-1)<1
解方程log4(3x+1)=log4x+log4(3+x)
解方程log4(3x+1)=log4x+log4(3+x).会的帮帮忙,