计算:{[-1/6x^(2n+1)y^(2n+1)+1/3x^(2n+1)y(^(2n-1)+1/2x^(2n-1)y^(2n-1)]}/[-1/12x^(2n-1)y^(2n-1)](^*__*^)
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计算:{[-1/6x^(2n+1)y^(2n+1)+1/3x^(2n+1)y(^(2n-1)+1/2x^(2n-1)y^(2n-1)]}/[-1/12x^(2n-1)y^(2n-1)](^*__*^)
计算:{[-1/6x^(2n+1)y^(2n+1)+1/3x^(2n+1)y(^(2n-1)+1/2x^(2n-1)y^(2n-1)]}/[-1/12x^(2n-1)y^(2n-1)](^*__*^)
计算:{[-1/6x^(2n+1)y^(2n+1)+1/3x^(2n+1)y(^(2n-1)+1/2x^(2n-1)y^(2n-1)]}/[-1/12x^(2n-1)y^(2n-1)]
(^*__*^)
计算:{[-1/6x^(2n+1)y^(2n+1)+1/3x^(2n+1)y(^(2n-1)+1/2x^(2n-1)y^(2n-1)]}/[-1/12x^(2n-1)y^(2n-1)](^*__*^)
（提公因式）
-1/6x^(2n+1)y^(2n+1)+1/3x^(2n+1)y(^(2n-1)+1/2x^(2n-1)y^(2n-1)
=-1/6x^(2n-1)y^(2n-1)[x^2y^2+2x^2+3x^(2n-1)]
所以
原式=-1/6x^(2n-1)y^(2n-1)[x^2y^2+2x^2+3x^(2n-1)]/[-1/12x^(2n-1)y^(2n-1)]
=2(x^2y^2-2x^2-3)
2(x^2y^2-2x^2-3)
1:分子上提取公因式：x^(2n-1)y^(2n-1)[-1/6x平方y平方+1/3x平方+1/2]
2:再比上分母得：2x平方y平方-4x平方-6
/是什么意思。
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计算:{[-1/6x^(2n+1)y^(2n+1)+1/3x^(2n+1)y(^(2n-1)+1/2x^(2n-1)y^(2n-1)]}/[-1/12x^(2n-1)y^(2n-1)](^*__*^)
计算:{[-1/6x^(2n+1)y^(2n+1)+1/3x^(2n+1)y(^(2n-1)+1/2x^(2n-1)y^(2n-1)]}/[-1/12x^(2n-1)y^(2n-1)]
初一下平方差公式计算(过程详细)(1).(3x+7y)(3x-7y0(2).(0.2x-0.3)(0.2x+0.3)(3).(mn-3n)(mn+3n)(4).(-2x+3y)(-2x-3y)(5).(-1/4x-2y)(-1/4x+2y)(6).x^2+(y-x)(y+x)(7).(a^n+b)(a^n-b)(8).(a+1)(a-1)(a^2+1)1).(3x+7y)(3x-7y)
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