(1+x^2)y'-2xy=(1+x^2)^2求微分的通解
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(1+x^2)y''-2xy=(1+x^2)^2求微分的通解(1+x^2)y''-2xy=(1+x^2)^2求微分的通解(1+x^2)y''-2xy=(1+x^2)^2求微分的通解y=(x^2+1)(x+C
(1+x^2)y'-2xy=(1+x^2)^2求微分的通解
(1+x^2)y'-2xy=(1+x^2)^2求微分的通解
(1+x^2)y'-2xy=(1+x^2)^2求微分的通解
y=(x^2+1)(x+C)
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.(x+y-2)(x+y-2xy)+(xy-1)^2
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若x-y=4,xy=1,则(2x+y-2xy)-(3x+2y+xy)-(4xy+3y-5x)=