f(xy,x-y)=x^2+y^2,则fx(x,y)+fy(x,y)=
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f(xy,x-y)=x^2+y^2,则fx(x,y)+fy(x,y)=f(xy,x-y)=x^2+y^2,则fx(x,y)+fy(x,y)=f(xy,x-y)=x^2+y^2,则fx(x,y)+fy(
f(xy,x-y)=x^2+y^2,则fx(x,y)+fy(x,y)=
f(xy,x-y)=x^2+y^2,则fx(x,y)+fy(x,y)=
f(xy,x-y)=x^2+y^2,则fx(x,y)+fy(x,y)=
f(xy,x-y)=x^2+y^2=(x-y)^2+2xy
所以
f(x,y)=2x+y^2
fx=2
fy=2y
f(x+y)=f(x)+f(y)+2xy
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