已知α∈(π/2,π),sin(-α-π)=根号5/5,则sin(α-3/2π)=

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已知α∈(π/2,π),sin(-α-π)=根号5/5,则sin(α-3/2π)=已知α∈(π/2,π),sin(-α-π)=根号5/5,则sin(α-3/2π)=已知α∈(π/2,π),sin(-α

已知α∈(π/2,π),sin(-α-π)=根号5/5,则sin(α-3/2π)=
已知α∈(π/2,π),sin(-α-π)=根号5/5,则sin(α-3/2π)=

已知α∈(π/2,π),sin(-α-π)=根号5/5,则sin(α-3/2π)=
sin(-a-π)=sina=√5/5
sin²a+cos²a=1
cosa