2log3 2-log32/9+log3 8-5^log5 3
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2log32-log32/9+log38-5^log532log32-log32/9+log38-5^log532log32-log32/9+log38-5^log53应用公式：①log3(M/N)=
2log3 2-log32/9+log3 8-5^log5 3
2log3 2-log32/9+log3 8-5^log5 3
2log3 2-log32/9+log3 8-5^log5 3
应用公式：
①log3(M/N)=log3(M)-log3(N)
②log3(Mⁿ)=nlog3(M)
③M^logM(N)=N
2log3(2)-log3(2/9)+log3(8)-5^log5(3)
=2log3(2)-[log3(2)-log3(9)]+3log3(2)-3
=2log3(2)-log3(2)+2log3(3)+3log3(2)-3
=4log3(2)+2-3
=4log3(2)-1
2log3^2-log3^(32/9)+log3^8-3
=log3^2^2-log3^(32/9)+log3^8-3
=log3^[2^2*8/(32/9)]-3
=log3^9-3
=log3^(3^2)-3
=2-3
=-1
2log3 2-log32/9+log3 8-5^log5 3
算 2log3 2-log32/9+log3 8-5^2log5 3 .
计算 2log3 2-log32/9+log3 8-5^log5 3
计算 2log3 2-log32/9+log3 8-5^log5 3
log3 2=m 试用m表示log32 18
知log3^2=m,用m表示log32^18
2-log32/9+log3 8-5的（2倍的log5 3）
2log3^2-log3^(32/9)+log3^8
(log3^14-log3^2)log7^9求值
log3 18-log3 2=log3 16?
已知log（32）9=p,log（27）25=q,适用p,q表示lg5p=log32(9)=2/5×log2(3)=2/5×1/log3(2)∴log3(2)=2/5pq=log27(25)=2/3×log3(5)∴log3(5)=3q/2lg5=log3(5)/log3(10)=log3(5)/[log3(2)+log3(5)]=15pq/(4+15pq)结果怎么出来的?
log3(log32) (log32)二次方比较大小
log3(2)*log8(9)
2log3 2-log3 32/9+log3 8-3^2+log3 5
2log3 2-log3 32/9+log3 8-3^2+log3 5 明天要交的
已知log3 2=m,使用m表示log32 18过程
已知log3（2）=m,试用m表示log32（18）
你可以将原式变为 log23+log32 =log23/log22+log22/log33 =log3/1+1/log3 =log3+1/log3 相信你知道log(2)xalogaM=M怎么算的