2log3^2-log3^(32/9)+log3^8
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2log3^2-log3^(32/9)+log3^82log3^2-log3^(32/9)+log3^82log3^2-log3^(32/9)+log3^82log3^2-log3^(32/9)+lo
2log3^2-log3^(32/9)+log3^8
2log3^2-log3^(32/9)+log3^8
2log3^2-log3^(32/9)+log3^8
2log3^2-log3^(32/9)+log3^8
=log3^2^2-log3^(32/9)+log3^8
=log3^[2^2*8/(32/9)]
=log3^9
=log3^(3^2)
=2
2log3^2-log3^(32/9)+log3^8
2log3 2-log3 32/9+log3 8-3^2+log3 5
2log3 2-log3 32/9+log3 8-3^2+log3 5 明天要交的
(log3^14-log3^2)log7^9求值
2log3 2-log3 32/9+log3 8-5^2log5 3
2log3^2-log3^(32/9)+log3^8 怎么化简?
2log3 (2)-log3(32/9)+log3(8)-3详细解答!
log3 18-log3 2=log3 16?
log3(2)*log8(9)
2log3^2-log3^(32/9)+log3^8-5log5^3=5log5^3改成5^log5^3
求值:2log3(这个3是角标）2-log3（角标）32/9+log3（角标）8-5log
2log3 2-log32/9+log3 8-5^log5 3
计算log3[(9^2 * 27^(1/3))/3^(log3 234)]
计算9^log3 4+2
解不等式（2+log3 x)log3 x>log3 (9x)3都是底数
log2(3)+log3(5)+log3(2)=?
log3 8除以log3 2怎么计算
请问log3 18-log3 2等于多少