X3-4xy2-2x2y+8y3(x2+x)2-8(x2+x)+1212x2-5x-25x2+6xy-8y2x4+64x3-11x2+31x-213a3b-81b4a7-ab6ab(c2-d2)+cd(a2-b2)4x4-13x2+9(x2-2x)2-7(x2-2x)+12x2+x-(a2-a)本人很笨,可以的话写得详细清楚点.

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X3-4xy2-2x2y+8y3(x2+x)2-8(x2+x)+1212x2-5x-25x2+6xy-8y2x4+64x3-11x2+31x-213a3b-81b4a7-ab6ab(c2-d2)+cd

X3-4xy2-2x2y+8y3(x2+x)2-8(x2+x)+1212x2-5x-25x2+6xy-8y2x4+64x3-11x2+31x-213a3b-81b4a7-ab6ab(c2-d2)+cd(a2-b2)4x4-13x2+9(x2-2x)2-7(x2-2x)+12x2+x-(a2-a)本人很笨,可以的话写得详细清楚点.
X3-4xy2-2x2y+8y3
(x2+x)2-8(x2+x)+12
12x2-5x-2
5x2+6xy-8y2
x4+64
x3-11x2+31x-21
3a3b-81b4
a7-ab6
ab(c2-d2)+cd(a2-b2)
4x4-13x2+9
(x2-2x)2-7(x2-2x)+12
x2+x-(a2-a)
本人很笨,可以的话写得详细清楚点.

X3-4xy2-2x2y+8y3(x2+x)2-8(x2+x)+1212x2-5x-25x2+6xy-8y2x4+64x3-11x2+31x-213a3b-81b4a7-ab6ab(c2-d2)+cd(a2-b2)4x4-13x2+9(x2-2x)2-7(x2-2x)+12x2+x-(a2-a)本人很笨,可以的话写得详细清楚点.
x^3-4xy^2-2x^2y+8y^3
=x^2(x-2y)-4y^2(x-2y)
=(x-2y)(x^2-4y^2)
=(x-2y)^2(x+2y)
(x^2+x)^2-8(x^2+x)+12
=(x^2+x-6)(x^2+x-2)
=(x+3)(x-2)(x+2)(x-1)
12x^2-5x-2
=12x^2+3x-8x-2
=3x(4x+1)-2(4x+1)
=(3x-2)(4x+1)
5x^2+6xy-8y^2
=(x+2y)(5x-4y).
x^4+64
=x^4+16x^2+64-16x^2
=(x^2+8)^2-16x^2
=(x^2+4x+8)(x^2-4x+8)
x³-11x²+31x-21
=(x³-x²)-(10x²-10x)+(21x-21)
=x²(x-1)-10x(x-1)+21(x-1)
=(x²-10x+21)(x-1)
=(x-3)(x-7)(x-1)
=(x-1)(x-3)(x-7)
3a3b-81b4
=3b(a^3-27b^3)
=3b(a-3b)(a^2+3ab+9b^2)
a7-ab6
=a(a^6-b^6)
=a(a^3+b^3)(a^3-b^3)
=a(a-b)(a^2+ab+b^2)(a+b)(a^2-ab+b^2)
ab(c^2-d^2)+cd(a^2-b^2)
=abc^2-abd^2+a^2cd-cb^2d
=abc^2+a^2cd-cb^2d-abd^2
=ac(bc+ad)-bd(cb+ad)
=(bc+ad)(ac-bd)
4x^4-13x^2+9
=(4x^2-9)(x^2-1)
=(2x+3)(2x-3)(x+1)(x-1)
(x^2-2x)^2-7(x2-2x)+12
=(x^2-2x-4)(x^2-2x-3)
=(x^2-2x-4)(x-3)(x+1)
x^2+x-(a^2-a)
=x^2-a^2+x-a
=(x-a)(x+a)+x-a
=(x-a)(x+a+1)

x3+2x2y+2xy2+y3因式分解 (4xy2-2x2y)-( )=x3-2x2y+4xy2+y3. x.y取何值时,代数(x3y+3x2y-5xy2+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y3).y取何值时,代数(x3y+3x2y-5xy2+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y3)的值都是常数? 试说明代数式(x3+3x2y-4xy2+6y3)-(2x3-x2y-xy2-y3-1)+(x34x2y+3xy2-7y3)的值与xy取值无关 因式分解:x3-y3-x2y+xy2 x3+x2y-xy2-y3= 分解因式:X3+2X2Y+2XY2+Y3= 分解因式 x3+y3-x2y-xy2 x3-y3-x2y+xy2分解因式 分解因式x3-xy2+x2y-y3 试说明:无论x,y取何值时,代数式(x3+3x2y-5+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y2)的值是常数.要具体过程,注意格式 求方程x3+x2y+xy2+y3=8(x2+xy+y2+1)的全部整数解 x2+x2y-xy2-y3得值 若x3+y3=1000,x2y-xy=-496,则(x3-y3)+(4xy2-2x2y)-2(xy2-y3)= ---- 若m=x3-3x2y+2xy2+3y2 n=x3-2x2y+xy2-5y3,则2x3-7x2y+5xy2+14y2等于( )若m=x3-3x2y+2xy2+3y2 n=x3-2x2y+xy2-5y3,则2x3-7x2y+5xy2+14y2等于( )空里用字母表示 分解因式 1)4x3+8x2-x-2 2)x3x2y-xy2-y3 3)x2y-xy2+2x-2y 4)x2-4y2-x+2y分解因式 1)4x3+8x2-x-2 2)x3x2y-xy2-y3 3)x2y-xy2+2x-2y 4)x2-4y2-x+2y 5)ac-bc-a2+2ab-b2 6)a3+a2b-a2c-abc 7)x2-2x-b2-2b 8)5a2m+6abm-10a2n-12abn9)-xy+bx+ay-ab 10)a(b-c)+a2-bc 11)x 当x=2014求代数式(2x3一3x2y一2xy2)一(x3一2xy2十y3)十(一x3十3x2十y3)的值 已知A=x3-2y3+3x2y+xy2-3xy+4,B=y3-x3-4x2y-3xy-3xy2+3,C=y3+x2y+2xy2+6xy-6,试着说明对于x,y,z的任何值,A+B+C是常数.某同学做一道代数题:求代数式10x9+9x8+8x7+…+3x2+2x+1,当x=-1时