已知sinx+siny+sinz=0,cosx+cosy+cosz=0,求证cos(x-y)=cos(y-z)=cos(z-x)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/28 21:02:51
已知sinx+siny+sinz=0,cosx+cosy+cosz=0,求证cos(x-y)=cos(y-z)=cos(z-x)已知sinx+siny+sinz=0,cosx+cosy+cosz=0,
已知sinx+siny+sinz=0,cosx+cosy+cosz=0,求证cos(x-y)=cos(y-z)=cos(z-x)
已知sinx+siny+sinz=0,cosx+cosy+cosz=0,求证cos(x-y)=cos(y-z)=cos(z-x)
已知sinx+siny+sinz=0,cosx+cosy+cosz=0,求证cos(x-y)=cos(y-z)=cos(z-x)
由sinx+siny+sinz=0可得(sinx+siny)²=(-sinz)²,展开为sin²x+sin²y+2sinxsiny=sin²z (1)
同理cosx+cosy+cosz=0可得cos²x+cos²y+2cosxcosy=cos²z (2)
(1)(2)式相加可得2+2(cosxcosy+sinxsiny)=1
所以cos(x-y)=cosxcosy+sinxsiny=-1/2
同样的也可以得到cos(y-z)=-1/2和cos(z-x)=-1/2
所以这三个余弦是相等的.
已知sinx+siny+sinz=0,cosx+cosy+cosz=0 则cos(x-y)=______ 要详解
已知sinx+siny+sinz=cosx+cosy+cosz=0,求tan(x+y+z)+tanxtanytanz的值
sinx+siny+sinz=0;cosx+cosy+cosz=0;求cos(x-y)
已知sinx+siny+sinz=0,cosx+cosy+cosz=0,求证cos(x-y)=cos(y-z)=cos(z-x)
已知x,y,z属于(0,派/2),sin^2x+sin^2y+sin^2z=1,求(sinx+siny+sinz)/(cosx+cosy+cosz)的最大值
一道关于三角函数的不等式证明题已知0≤x<y<z≤π求证:(siny-sinx)/(y-x)>(sinz-siny)/(z-y)
1.已知8cos(2x+y)+5cosy=0,求tan(x+y)*tanx的值.2.已知关于x的方程x^2+px+q=0的两根是tanx,tany,求sin(x+y)/cos(x-y)的值.3.化简:sin(x-y)/(sinx*siny)+sin(y-z)/(siny*sinz)+sin(z-x)/(sinz*sinx).
sinx+siny+sinz=0,cosx+cosy+cosz=0,求cos(y-z)的值.
已知x,y,z均为锐角,且sinx+sinz=siny,cosx-cosz=cosy,求x-y的值.
已知sinx+siny=1/3,sinx-siny的最小值已知sinx+siny=1/3,sinx-已知sinx+siny=1/3,sinx-siny的最小值是
sinX+sinY+sinZ=0 同时满足cosX+cosY+cosZ=0求cos(X-Y)为何值?所有的条件就这些了,我只要答案,
已知1+cosx-siny+sinx*siny=0,1-cosx-cosy+sinx*cosy=0,求sinx的值
已知1+cosx-siny+sinx*siny=0,1-cosx-cosy+sinx*cosy=0.求Sinx.
关于三角函数的计算已知SinX+SinY=2/3求 SinX-SinY=?怎么算?
m=(sinx)/sin(y-z),n=(siny)/sin(z-x),p=(sinz)/sin(x-y),求mn+np+pm.
若sinx+sinz=2siny,求证:tan((x+y)/2)+tan((y+z)/2)=2tan((x+z)/2)
证明sinx+siny+sinz-sin(x+y+z)=4sin((x+y)/2)sin((x+y)/2)sin((x+y)/2)
将sinx+siny+sinz-sin(x+y+z)化为积的形式