设A={y|y=sin(x+π/6),0

设A={y|y=sin(x+π/6),0 设全集为R,集合A={y/y=sin(2x-π/6),π/4 设函数 f(x)=sin(2x+y),(-π 设函数y=3sin(2x+φ)（0 设x∈[0,π],y∈[0,1],试求函数f(x,y)=(2y-1)sinx+(1-y)sin[(1-y)x]的最小值. y=sin(2x+a)(0 y=sin(2x+a)（0 设A={(x,y)/x+y 设y=y(x)由方程cos(x+y)+y=1,求dy/dx我做到-sin(x+y)*(x+y)'+y'=0 设函数f（x,y)=sin(x+y),那么f(0,xy）=( ) 设集合A={(x,y)/0 设集合A={(x,y)/0 设y=sinx²+sin²x,求y'rt设y=ln(2x+1)，求y 设f可导,y=sin{f[sin（x）]}且f（0）=0,求y'(0) 设sin(x+y)sin(x-y)=m,则cos^2x-cos^2y的值 设方程e^(x+y) + sin(xy) = 1 确定的隐函数为y=y(x),求y'和y'|x=0 设y=y(x)是由方程e^x-e^y=sin(xy)所确定,求y',y'｜x=0 设sin(x+y)=xy,求dy/dx.