【化简】2/b√ab^5·(-3/2√a^3b)÷√b/a(a>0,b>0)

已知a-2√ab+b=0(a>0,b>0),求(3a-√ab+b)/(5a+3√ab-4b)的值 先化简,再求值:(A^2-2/A^2-AB^2+2-A^2B-AB^2)/(A^2+AB/2AB+B^2+ab/2ab),其中A=5-√11,B=3+√11 化简：1.3a+2b-5a-b 2.3(-ab+2a)-2(3a-ab) 【化简】2/b√ab^5·(-3/2√a^3b)÷3√b/a(a>0,b>0) 化简,3ab√a²b³÷5√b/a×2/5√a/b 【化简】2/b√ab^5·(-3/2√a^3b)÷√b/a(a>0,b>0) (a- √ab -2b)分之(a - 2√ab) +(a√a + b√b)分之(a√b -b√a +b√b) 化简 a^2b-ab+2ab^2-5a^b-4ab+3ab^2化简快 化简(√a+√b+√ab)^2-(√a+√b-√ab)^2 化简[2/b*√(ab^5)]*(-2/3*√a^3b)÷3√(b/a) 化简 5ab-[2(2a^2-ab-b^2)-3(a^2+b^2)]-3(ab-2b^2) -ab(a^2b^5-ab^3-b) 化简:(-2ab+3a)-(2a-b)+6ab 化简 5(3a ^2 b-ab ^2 )-(ab ^2 +3a ^2 b) 化简:5(3a^2b-ab^2)-4(-ab^2+3a^2b) 已知√a(√a+√b)=3√b×(2/3×√a+4√b),其中ab≠0,求（a-5b+√ab)/a+b+√ab的值~ √a(√a+√b)=3√b(2/3√a+4√b),其中ab不等于0,求a-5b+√ab/a+b+√ab的值? 1.已知a=2+√3b=2-√3求：（（√ab）+（ab/（a-2√ab））)/（(2√ab-b)/（a-b））注：√ab都是根号下ab2.若a、b为有理数,（a+√3）*（a+√3）=b-8√3求：a-b3.a+b=2√（ab）a大于0,b大于0求√(a+b)与√（3a+5b