化简【cos(π/4+α)-sin(π/4+α)】/【cos(π/4-α)+sin(π/4-α)】.如题

化简sin(π/4+α)cosα-sin(π/4-α)sinα 化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π) 化简sin(α-2π)+sin(-a-3π)cos(α-3π)/cos(π-α)-cos(-π-α)cos(α-4π) 化简sin(π/4-α)+cos(π/4+α) 化简【cos(π/4+α)-sin(π/4+α)】/【cos(π/4-α)+sin(π/4-α)】.如题 化简:sin(π/4-α)cos(π/3-α)-cos(π/6+α)sin(π/4+α)= 化简：[1+2sin(α+2π)*cos(α-2π)]/[sin(α+4π)+cos(α+8π)] 化简：2cos²α-1/【2sin(π/4-α)sin²(π/4+α)】 化简：2cos²α-1/【2sin(π/4-α)sin²(π/4+α)】 求值：（tan10°-√3）×cos10°/sin50° 求证：[sin（2α+β）]/sinα- 2cos（α+β）=sinβ/cosα 化简cosθ+cos（θ+2π/3）+cos（θ+4π/3） 证明：sin（α+β）sin（α-β）=sin^2α-sin^2β 化简：cosα+sinα+a²sin(α+π/4) 利用和差角公式化简 (2)sin(π/3+α)+sin(π/3-α)(2)sin(π/3+α)+sin(π/3-α)(3)cos(π/4+α)-cos(π/4-α)(4)cos(60°+α)+cos(60°-α)(5)sin(α-β)cosβ+cos(α-β)sinβ(6)cos(α+β)cosβ+sin(α+β)sinβ 化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π/2+α) 化简 {sin(π+α)cos(α-2π)tan9π/4}/sin(-α)sin(7π/2+α)过程 cos^2(π/4+α)=(cos(π/4)cosα-sin(π/4)sinα)² cos^2(π/4+α)是怎么等于(cos(π/4)cosα-sin(π/4)sinα)²的? [sin(5π-α)cos(-π-α)]/[cos(α-π)cos(π/2+α)]化简 化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α) (1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 （3/2*π