化简:(sinx+cosx-1)(sinx-cosx+1)/sin2x
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化简:(sinx+cosx-1)(sinx-cosx+1)/sin2x化简:(sinx+cosx-1)(sinx-cosx+1)/sin2x化简:(sinx+cosx-1)(sinx-cosx+1)/
化简:(sinx+cosx-1)(sinx-cosx+1)/sin2x
化简:(sinx+cosx-1)(sinx-cosx+1)/sin2x
化简:(sinx+cosx-1)(sinx-cosx+1)/sin2x
(sinx+cosx-1)(sinx-cosx+1)/sin2x
=[(sinx)^2-(cosx-1)^2]/sin2x
=[(sinx)^2-(cosx)^2+2cos-1]/sin2x
={-[1-(sinx)^2]-(cosx)^2+2cos}/sin2x
=[-(cosx)^2-(cosx)^2+2cos]/sin2x
=2[cosx-(cosx)^2]/2sinxcosx
=(1-cosx)/sinx
=2[sin(x/2)]^2/2sin(x/2)cos(x/2)
=sin(x/2)/cos(x/2)
=tan(x/2)
[sinx+(cosx-1)][(sinx-(cosx-1)]/2sinxcosx
=[(sinx)^2-(cosx)^2+2cosx-1]/2sinxcosx
=-cotx+1/sinx
化简[sin^2(x)]/(sinx-cosx)-(sinx+cosx)/[tan^2(x)-1]-sinx
化简cosX +sin X) /(cosX -sinX)
化简(cosX +sin X) /(cosX -sinX)
化简(sin^2x/sinx-cosx) -(sinx +cosx/tan^2x-1)
化简sin^4x/sinx-cosx - (sinx+cosx)cos^2x/tan^2x-1
(sin^x/sinx-cosx)-sinx+cosx/tan^2x-1
化简:(1+sinx+cosx) / (1+sinx-cosx)
1+sinx-cosx/1+sinx+cosx 化简
求证sin^2x/sinx-cosx-(sinx+cosx)/(tan^2-1)=sinx+cosx谢谢GGJJ
求证 sin^2x/(sinx-cosx)-(sinx+cosx)/tan^2 x-1=sinx+cosx
cosx-sinx/1+sin^2x不定积分
化简:(1+cosx-sinx)/(1-cosx-sinx)+(1-cosx-sinx)/(1+cosx-sinx)
化简:(1+sinx+cosx/1+sinx-cosx) + (1+sinx-cosx/1+sinx+cosx)
证明(1+secx+tanx)/(1+secx-tanx)=(1+sinx)/cosx左边=(cosx/cosx+1/cosx+sinx/cosx)/(cosx/cosx+1/cosx-sinx/cosx)=(cosx+1+sinx)/(cosx+1-sinx)=(cosx+1+sinx)^2/[(cosx+1+sinx)(cosx+1-sinx)]=(cos²x+sin²x+2*sinx*cosx+2*cosx+2*sinx+1)/(cos²
化简((sinx+cosx -1)(sinx-cosx+1)-2cosx)/sin2x
化简((sinx+cosx-1)(sinx-cosx+1)-2cosx)/sin2x
化简:sinx/(sinx-cosx) -(sinx+cosx)/(tanx-1)
化简:(sinx)^2/(sinx-cosx)-(sinx+cosx)/((tanx)^2-1)