求证 sin^2x/(sinx-cosx)-(sinx+cosx)/tan^2 x-1=sinx+cosx

求证 sin^2x/(sinx-cosx)-(sinx+cosx)/tan^2 x-1=sinx+cosx 求证sin^2x/sinx-cosx-(sinx+cosx)/(tan^2-1)=sinx+cosx谢谢GGJJ 求证sinx-cosx=根号2sin(x-π/4) (sin^x/sinx-cosx)-sinx+cosx/tan^2x-1 （1）已知：(4sinx-2cosx)/(5cosx+3sinx)=6/11 求sinx乘以cosx的值（2）证明(cosx/1+sinx) - (sinx/1+cosx)=2（cosx-sinx)/1+sinx+cosx(3)求证:sin²x乘以tanx + cos²x乘以cotx+2sinx乘以cosx=tanx+cotx要用 sin²X+cos²X=1 求证:Sin^2 x / (sinx-cosx) - (sin x + cos x)/(ta求证:Sin^2 x / (sinx-cosx) - (sin x + cos x)/(tan^2-1) = sin x + cos x sinx+cosx/sinx-cosx=2 求sinx/cos^3x +cosx/sin^3x 证明:sin2x=2sinx*cosx为什么sin(x+x)=sinx*cosx+cosx*sinx? 1-2sinx cosx /COS^2X-SIN^2X =1-tanx/1+tanx 求证 cosx-sinx/1+sin^2x不定积分 ∫sinx/(cosx-sin^2x)dx 求证：更号3cosX-sinX=2sin(派/3-x) 求证 sinx(cos^2 2x-sin^2 2x) + 2cosx cos2x sin2x= sin 5x 化简[sin^2(x)]/(sinx-cosx)-(sinx+cosx)/[tan^2(x)-1]-sinx 利用cosx=sin(π/2-x),sin'x=cosx,证明(cosx)'=-sinx 3sinx-2cosx=0 (1)(cosx-sinx)/(cosx+sinx)+(cosx+sinx)/(cosx-sinx) (2)sin^2 x-2sinxcosx+4cos^2 x (1+Sinx+Cosx+SinxCosx)/(Sinx+Sin^2 x)怎么化简成(Cscx+1+Cotx+Cosx)/(1+Sinx)? 证明(1+secx+tanx)/(1+secx-tanx)=(1+sinx)/cosx左边=（cosx/cosx+1/cosx+sinx/cosx)/（cosx/cosx+1/cosx-sinx/cosx)=(cosx+1+sinx)/(cosx+1-sinx)=(cosx+1+sinx)^2/[(cosx+1+sinx)(cosx+1-sinx)]=(cos²x+sin²x+2*sinx*cosx+2*cosx+2*sinx+1)/(cos²