求证sinx-cosx=根号2sin(x-π/4)
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求证sinx-cosx=根号2sin(x-π/4)求证sinx-cosx=根号2sin(x-π/4)求证sinx-cosx=根号2sin(x-π/4)√2sin(x-π/4)=√2(sinxcosπ/
求证sinx-cosx=根号2sin(x-π/4)
求证sinx-cosx=根号2sin(x-π/4)
求证sinx-cosx=根号2sin(x-π/4)
√2 sin(x-π/4)=√2(sinxcosπ/4-cosxsinπ/4)
=√2[(1/√2)sinx - (1/√2)cosx]
=sin x - cos x
Sinx-Cosx
=√2(√2/2Sinx-√2/2Cosx)
因为Sinπ/4=Cosπ/4=√2/2
所以原式=√2(Cosπ/4Sinx-Sinπ/4Cosx)
=√2Sin(x-π/4)
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