s="ABBACDDBA"ForI=6To2,step-2 x=Mid(s,I,I) y=left(s,I) z=rigt(s,I) Next I Msgbox z End sub结果是多少啊,要分析
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s="ABBACDDBA"ForI=6To2,step-2x=Mid(s,I,I)y=left(s,I)z=rigt(s,I)NextIMsgboxzEndsub结果是多少啊,要分析s="ABBACD
s="ABBACDDBA"ForI=6To2,step-2 x=Mid(s,I,I) y=left(s,I) z=rigt(s,I) Next I Msgbox z End sub结果是多少啊,要分析
s="ABBACDDBA"ForI=6To2,step-2 x=Mid(s,I,I) y=left(s,I) z=rigt(s,I) Next I Msgbox z End sub
结果是多少啊,要分析
s="ABBACDDBA"ForI=6To2,step-2 x=Mid(s,I,I) y=left(s,I) z=rigt(s,I) Next I Msgbox z End sub结果是多少啊,要分析
Private Sub Form_Load()
s = "ABBACDDBA"
For I = 6 To 2 Step -2
'x = Mid(s, I, I)
'y = Left(s, I)
'通过 MsgBox z 可知,结果与 x,y 没关系
z = Right(s, I)
'从这里可以看出 z 的值每一次循环都把之前的值覆盖
'掉.所以,只是循环的最后一次起作用,已知每次循
'环 I分别为 6,4,2,最后一次是 2 ,所以 z=Right(s,2)
'z 取 "ABBACDDBA" 的右边两个 即是 "BA".
Next I
MsgBox z
End Sub
'结果是 BA .
s=ABBACDDBAForI=6To2,step-2 x=Mid(s,I,I) y=left(s,I) z=rigt(s,I) Next I Msgbox z End sub结果是多少啊,要分析
Fori=(1)To 5 Step-1 S=s+1 Neti 要是循环体s=s+1执行三次则(1)应该是
在线等fori:=0tocountdoregisterserviceprocess(intout_insert()structout_product*p1,*p;
已知程序段:s=0 Fori=1 to 10 step2 s=s+1 i=i*2 Nexti 当循环结束后,变量i的值为( ),变量s的值为(
【VB】执行下面程序段后,变量s的值为.S=0ForI = 1 To 10 Step 2S =S + INextI(A)55 (B) 25 (C) 50 (D) 30
例如four=forI=? White=? son=? pears=?
在VB中:Fori=3 To 27 Step 循环几次啊?
计算VB程序机题目求1到100之间能被6整除的个数求1到100之间能被6整除的个数s=0fori=1to100if(1)thens=s+1next iprint1到100之间能被6整除的个数是:;(2)end sud1和2填什么
VB程序如下:Dim a a = Array(1,2,3,4,5,6,7,8) i = 0 For k = 100 To 90 Step -2完全看不懂...要详解..VB程序如下:Dim aa = Array(1,2,3,4,5,6,7,8)i = 0 For k = 100 To 90 Step -2s = a(i)^2If a(i) > 3 Then Exit Fori = i + 1Next kPrint k; a(
v=s/t
英语翻译sorrymaybe it's too latebut reallysorrymaybe it's not just one thing i should apologize forI shouldn't have pissed you like thatto tell the truthI haven't made someone mad enough to cryforgive my unwisdomI didn't know you would be like
s-2t/3s•6s平方/s+2t=谢谢急!求过程!
英语翻译How,do I put it to words That one thing is for sureYou're the one I'm here forI ,I come running to youNothing I wouldn't do I wouldn't here desert you,hurt youI want you to knowWho's gone be hereSanding by your side foreverWho's gonna hel
S=1-t+t^2求导,
t=t&mid(s,i,
3t+4s=-2,5t-6s=3过程,
利用加减消元法解方程组:2s+3t=2 2s-6t=-1
解下列二元方程组 3s-5t=6 s+4t=-15