for(i=1,j=1;j=2&&(i

for(j=i+1;j 怎么用lingo求解多目标规划呢,max =@sum(I(i):@sum(J(j):@sum(link(I,J):x(i)*w(j)*p(i,j)/d(i,j))));@for(I(i):@sum(J(j)|w(j)#eq#1:x(i)*p(i,j))>0);@for(I(i):@sum(J(j):x(i)*p(i,j)*c(j))>0);@for(J(j):@sum(link(I,J):x(i)*p(i,j)>=0));@for(l for (j=i 谁能告诉我这两句代码的区别?这两句的区别?1：for(j=i;j>0;j--) if(a[j-1]>v){a[j]=a[j-1];ans++;} 2：for(j=i;j>0 && v for( int i=0,j=1; j < 5; j+=3 ) i=i+j; 为什么等于5 lingo程序求解释~n=@size(cities); min=@sum(link(i,j)|i#ne#j :distance(i,j)*x(i,j)); @sum(cities(i)|i#gt#1 :x(1,i))>=1; @for(cities(i)|i#gt#1:@sum(cities(j)|j#ne#i:x(j,i))=1; @for(cities(j)|j#gt#1#and#j#ne#i:level(j)>=level(i)+x(i,j)-(n-2)*(1-x(i, 向量i(i+j)+j(2j+3j)=? if语句用find函数怎么优化,程序如下：for i = 1:mfor j = 1:nif abs(R(i,j)-R1(i,j))>0.05R2(i,j) = R1(i,j)elseR2(i,j) = 0endif abs(G(i,j)-G1(i,j))>0.05G2(i,j) = G1(i,j)elseG2(i,j) = 0endif abs(B(i,j)-B1(i,j))>0.05B2(i,j) = B1(i,j)elseB2(i,j) 2个矩阵相加,For i = 1 To 4For j = 1 To 4c(i,j) = a(i,j) + b(i,j)Picture3.Print c(i,j);If i = 1 And j = 1 ThenMax = c(i,j)ElseIf Max < c(i,j) Then Max = c(i,j):n = i:m = jEnd IfNext jPicture3.PrintNext i这个和For i = 1 To 4For j = 1 To 4c(i,j) for(i=1;i<10;i++){for(j=1;j<=i;j++)解释一下这是什么意思? main() {int i,j,w=0; for(i=4; i; i--) for(j=1;j int i=2,j=1,k=3 i&&(i+j)&k|i+j 2、 FOR （I=1,j=20；I string.Format({0}*{1}={2},i,j,i*j); for(i=1,j=1;j=2&&(i 以下程序段的运行结果是（ ）.int a[]={1,2,3,4},i,j; j=1; for(i=3;i>=0;i--) {a[i]=a[i]*j; j=j*3; } f以下程序段的运行结果是（ ）.int a[]={1,2,3,4},i,j;j=1;for(i=3;i>=0;i--){a[i]=a[i]*j;j=j*3;}for(i=0;i for(j=1;j<=n;j++) { for(i=1;i<m;i++) 数据结构,怎么循环 int i,j=2;*p=&i;*p=(*&j+1)^j; i=?