等差数列题目S(n+1)/Sn=(n+2)/n,求An

等差数列题目S(n+1)/Sn=(n+2)/n,求An 两个等差数列{an},(bn}前n项和分别为Sn,S'n,若Sn/S'n=(2n+3)/(3n-1)求a9/b9 等差数列A1=1,前 n项和满足S（2n-1）/Sn=（4n+2）/n+11.求通项an2.设Bn=1/sn,求前n项和Tn今天我们老师改了题目，是S（2n-1）/Sn=（4n-2）/n+1 等差数列A1=1,前 n项和满足S（2n-1）/Sn=（4n+2）/n+1 1.求通项an2.设Bn=1/sn,求前n项和TnS（2n-1）/Sn=（4n-2）/n+1 老师改了题目 已知等差数列an中,a1=1,前n项和Sn,若S(n+1)/Sn=(4n+2)/(n+1),求an 已知等差数列an中,a1=1,前n项和Sn,若S(n+1)/Sn=(4n+2)/(n+1),求an 等差数列an前n项和为Sn,求证S（2n-1）=（2n-1）an 等差数列{an}前n项和为Sn,求证S 2n-1项=（2n-1）an 设等比数列 ｛an｝ 的公比为q,前n项和为Sn,若S(n+1),Sn,S(n+2)成等差数列,则q= 数列An的前n项和Sn,A(1)=1,A(n+1)=（n+2)Sn/n,证明1.Sn/n是等差数列 2.S(n+1)=4An 数列{an},前n项和sn,a1=2,a1、S(n+1)、4Sn成等差数列,求{an}通项公式、Sn 设等差数列{an}与{bn}的前n项之和为Sn,S`n,Sn/S`n=7n+2/n+3,求a7/b7 一道数学等差数列的题目等差数列an的前n项和Sn bn的前n项和Tn Sn比Tn=2n/(3n+1) 那么an与bn的比值是 a1=1,n,an,Sn成等差数列,证明｛Sn+n+2}是等比数列 已知数列an的前n项为Sn,且满足Sn=S(n-1)/2S(n-1)+1(n≥2）,a1=2(1)求证:{1/Sn}是等差数列(2)求an的表达式. 前N项和的相关题目等比数列a[n]前n项和为sn,已知s[1],2s[2],3s[3]成等差数列,则{a[n]}的公比为? 已知等差数列{an},{bn},它们的前n项和分别是Sn,S`n,若Sn/S`n=(2n+3)/(3n-1),则a9/b9=____请附上过程 已知两等差数列{an},{bn},它们的前n项和分别是Sn,S'n,若Sn/S'n=2n+3/3n-1,求a9/b9