函数y=[cos(x-π/12)]^2+[sin(x+π/12)]^2-1是周期为___的____(奇/偶)函数.
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函数y=[cos(x-π/12)]^2+[sin(x+π/12)]^2-1是周期为___的____(奇/偶)函数.函数y=[cos(x-π/12)]^2+[sin(x+π/12)]^2-1是周期为__
函数y=[cos(x-π/12)]^2+[sin(x+π/12)]^2-1是周期为___的____(奇/偶)函数.
函数y=[cos(x-π/12)]^2+[sin(x+π/12)]^2-1是周期为___的____(奇/偶)函数.
函数y=[cos(x-π/12)]^2+[sin(x+π/12)]^2-1是周期为___的____(奇/偶)函数.
y=[cos(x-π/12)]^2+[sin(x+π/12)]^2-1
=[1+cos(2x-π/6)]/2+[1-cos(2x+π/6)]/2-1
=[cos(2x-π/6)-cos(2x+π/6)]/2
=(1/2)*(-2)sin2xsin(-π/6)
=(1/2)sin2x
所以填入：π,奇
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