已知x的2方-x-1=0,求x的4方+1/(x的四方)

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已知x的2方-x-1=0,求x的4方+1/(x的四方)已知x的2方-x-1=0,求x的4方+1/(x的四方)已知x的2方-x-1=0,求x的4方+1/(x的四方)∵x^2-x-1=0,∴x^2=x+1

已知x的2方-x-1=0,求x的4方+1/(x的四方)
已知x的2方-x-1=0,求x的4方+1/(x的四方)

已知x的2方-x-1=0,求x的4方+1/(x的四方)
∵x^2-x-1=0,∴x^2=x+1,x=(1±√5)/2,1/x=(-1±√5)/2
x^4+1/x^4=(x^2-1/x^2)^2+2=[(x^4-1)/x^2]^2=[(x^2+1)(x^2-1)/x^2]^2=[(x+2)x/x^2]^2=(1+2/x)^2=5

原式两边同除X,然后两次平方,得1

x^2-x-1=0 可以推出x-1/x=1
因此
x^4+1/x^4=(x^4+1/x^4-2)+2=(x^2-1/x^2)^2+2=((x-1/x)(x+1/x))^2+2=(x+1/x)^2+2
=x^2+1/x^2+2+2=(x-1/x)^2+2+4=1+2+4=7