将y(y+1)(x^2+1)+x(2y^2+2y+1)因式分解RT

将y(y+1)(x^2+1)+x(2y^2+2y+1)因式分解RT [(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y x-y/x+y=-1/2,x*x-xy-2y*y/x*x-3xy+2y*y的解是多少?同上,请将过程写出, 1、y-x/x²-y²2、(x-y)(y-z)(z-x)/(z-y)(y-x)(x-z) (x-y)(2x-y-1) 将3(2x-y)-1/2(2x-y)的平方+(2x-y)-2(2x-y)+1/2(2x-y)的平方合并同类项 2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2 （x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3. [(-2x-y)^2-(2x+y)(2x-y)]÷2y-1/2y (x/x+y-x/y-x-2xy/x.x-y.y)/(1/x-1/y) 分式化简 x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x² 求(1+y)-2x(1+y)+x(1-y) 把4（x-y+1)+y(y-2x)因式分解 y(y+2)+4x(x-y-1)因式分解是多少 怎么将y=x^-x/x^-x+1化简成（y-1）x^2+(1-y)x+y=0急 将x(x+y)(x-y)-x(x+y)2进行因式分解,并求当x+y=1007,xy=-1时此式的值 (x-y/1-x+y/1)÷2y/y-x计算错了，是(1/x-y-1/x+y)÷2y/y-x 已知x+y=a,2x-y=-2a,求[（x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值